sample size would be required for the fraction nonconforming control chart if it is desired to have a probability of at least one nonconforming unit in the sample to be at least 0.95?

MATLAB: An Introduction with Applications
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Chapter1: Starting With Matlab
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**Question 3**

A process has an in-control fraction nonconforming of \( p = 0.02 \). What sample size would be required for the fraction nonconforming control chart if it is desired to have a probability of at least one nonconforming unit in the sample to be at least 0.95?

*Explanation:*

To solve this problem, we aim to determine the sample size \( n \) that ensures a probability of at least one nonconforming item being 0.95 or higher. This involves using the complement rule for probability, where the probability of at least one nonconforming unit is:

\[ P(\text{at least one nonconforming}) = 1 - P(\text{none are nonconforming}) \]

Given \( p = 0.02 \), the probability that a single unit is conforming (non-defective) is \( 1 - p = 0.98 \).

Thus, the probability that all units in a sample of size \( n \) are conforming is \( 0.98^n \).

Setting the complement probability to 0.95, we solve:

\[ 1 - 0.98^n \geq 0.95 \]

\[ 0.98^n \leq 0.05 \] 

To find \( n \), calculate:

\[ n \geq \frac{\log(0.05)}{\log(0.98)} \] 

This will give the required sample size to achieve the desired probability.
Transcribed Image Text:**Question 3** A process has an in-control fraction nonconforming of \( p = 0.02 \). What sample size would be required for the fraction nonconforming control chart if it is desired to have a probability of at least one nonconforming unit in the sample to be at least 0.95? *Explanation:* To solve this problem, we aim to determine the sample size \( n \) that ensures a probability of at least one nonconforming item being 0.95 or higher. This involves using the complement rule for probability, where the probability of at least one nonconforming unit is: \[ P(\text{at least one nonconforming}) = 1 - P(\text{none are nonconforming}) \] Given \( p = 0.02 \), the probability that a single unit is conforming (non-defective) is \( 1 - p = 0.98 \). Thus, the probability that all units in a sample of size \( n \) are conforming is \( 0.98^n \). Setting the complement probability to 0.95, we solve: \[ 1 - 0.98^n \geq 0.95 \] \[ 0.98^n \leq 0.05 \] To find \( n \), calculate: \[ n \geq \frac{\log(0.05)}{\log(0.98)} \] This will give the required sample size to achieve the desired probability.
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