Sample output with input: 283.15 10.0 C is 283.15 K 283.15 K is 10.0 C
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question

Transcribed Image Text:Using the celsius_to_kelvin function as a guide, create a new function, changing the name to kelvin_to_celsius,
and modifying the function accordingly.
Sample output with input: 283.15
10.0 C is 283.15 K
283.15 K is 10.0 C
Learn how our autograder works
461710 3116374.qx3zqy7
1 def celsius_to_kelvin (value_celsius):
value_kelvin = 0.0
12345
3
4
6
7 Your solution goes here """
8
9 value_c= 10.0
10 print(f' {value_c} C is {celsius_to_kelvin(value_c)} K')
11
value_kelvin value_celsius + 273.15
return value_kelvin
111
Run
12 value_k = float(input())
13 print(f' {value_k} K is {kelvin_to_celsius(value_k)} C')
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