4. A publishing company is studying the sales of various franchises in their chain of stores. They draw a randomsample of 75 stores in the chain, and measure the average daily sales. They find that sample mean is 5670 andsample standard deviation is 1750. Calculate a 90% confidence interval for the mean daily sales of their sales. *A. (5337.6, 6002.4)B. (2791.3, 8548.8)C. (5410.9, 5929.1)D. (3920.0, 7420.0)E. (5149.5, 6190.5)

Given that Sample size n =75 Sample mean =5670 Standard deviation =1750 90% confidence interval.

Answered: sample of 75 stores in the chain, and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Similar questions

For a certain type of job, it costs a copany an average of $231 to train an employee to perform the task. The standard deviation is $5. Find the minimum percentage of data values that will fall in the range of $219 to $243. Use Chebyshev's theorem.
A standardized exam's scores are normally distributed. In a recent year, the mean test score was 1466 and the standard deviation was 315. The test scores of four students selected at random are 1890, 1210, 2200, and 1340. Find the z-scores that correspond to each value and determine whether any of the values are unusual. The Z-score for 1890 is. (Round to two decimal places as needed.).
Use z scores to compare the given values. The tallest living man at one time had a height of 238 cm. The shortest living man at that time had a height of 142.4 cm. Heights of men at that time had a mean of 175.45 cm and a standard deviation of 5.59 cm. Which of these two men had the height that was more extreme? ... Since the z score for the tallest man is z = 0 and the z score for the shortest man is z = the man had the height that was Im- more extreme. (Round to two decimal places.) shortest tallest
Assume that adults have IQ scores that are normally distributed with a mean of 104.5 and a standard deviation 24.7. Find the first quartile Q,. which is the IQ score separating the bottom 25% from the top 75%. (Hint Draw a graph.) The first quartile is (Type an integer or decimal rounded to one decimal place as needed.)
Compute the standard deviation of the sampled proportions if p=.8 and n=50. Round to three places.
Consider a set of data in which the sample mean is 30.230.2 and the sample standard deviation is 7.87.8. Calculate the z-score given that x=31.4x=31.4. Round your answer to two decimal places.
On an intelligence test, the mean number of raw items correct is 236 and the standard deviation is 39. What are the raw (actual) scores on the test for people with IQs of (a) 119, (b) 81, and (c)100? To do this problem, first figure the Z score for the particular IQ score; then use that Z score to find the raw score. Note that IQ scores have a mean of 100 and a standard deviation of 15. (a) What is the raw (actual) score on the test for people with an IQ of 119?
In a class with 50 students, a 60-item test is conducted. After the test, it is found that the mean of the scores is 40 and the standard deviation is 5. Assuming normal frequency distribution, determine the scores of the students within 1 standard deviation.
how did you get the standard deviation of 4.8567 on the solution above?

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