Sample grams of a hydrocarbon, CxHy, were burned in a combustion analysis ap 5 of CO2 and 8.973 grams of H₂O were produced. e experiment, the molar mass of the compound was found to be 86.18 g e empirical formula and the molecular formula of the hydrocarbon. nter the elements in the order presented in the question. mpirical formula =

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### Combustion Analysis of a Hydrocarbon

When 6.130 grams of a hydrocarbon, \( C_xH_y \), were burned in a combustion analysis apparatus, 18.78 grams of \( CO_2 \) and 8.973 grams of \( H_2O \) were produced.

In a separate experiment, the molar mass of the compound was found to be 86.18 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon.

#### Explanation of Graph (Diagram)
The diagram shows a combustion analysis apparatus. The apparatus includes:
- **Furnace**: Where the sample is burned in the presence of \( O_2 \).
- **CO_2 Absorber**: A container that absorbs the \( CO_2 \) produced.
- **H_2O Absorber**: A container that absorbs the \( H_2O \) produced.

#### Calculations
To determine the empirical formula and the molecular formula, follow these steps:

1. **Find the number of moles of carbon and hydrogen**:
   - From the mass of \( CO_2 \): Obtain the moles of carbon.
   - From the mass of \( H_2O \): Obtain the moles of hydrogen.

2. **Determine the simplest whole number ratio of the elements**:
   - Use the moles calculated in the previous step to find the ratio.

3. **Calculate the empirical formula**:
   - Convert the ratio into the simplest whole numbers.

4. **Find the molecular formula**:
   - Use the molar mass to find the molecular formula based on the empirical formula.

#### Input Fields
Enter the elements in the order presented in the question.

Environmental formula = [        ]  
Molecular formula = [        ]

Once all fields have been filled, click on the "Check & Submit Answer" button.

For more details on the process, you can click the "Show Approach" button to see the detailed steps.

**Check & Submit Answer**
**Show Approach**
Transcribed Image Text:### Combustion Analysis of a Hydrocarbon When 6.130 grams of a hydrocarbon, \( C_xH_y \), were burned in a combustion analysis apparatus, 18.78 grams of \( CO_2 \) and 8.973 grams of \( H_2O \) were produced. In a separate experiment, the molar mass of the compound was found to be 86.18 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. #### Explanation of Graph (Diagram) The diagram shows a combustion analysis apparatus. The apparatus includes: - **Furnace**: Where the sample is burned in the presence of \( O_2 \). - **CO_2 Absorber**: A container that absorbs the \( CO_2 \) produced. - **H_2O Absorber**: A container that absorbs the \( H_2O \) produced. #### Calculations To determine the empirical formula and the molecular formula, follow these steps: 1. **Find the number of moles of carbon and hydrogen**: - From the mass of \( CO_2 \): Obtain the moles of carbon. - From the mass of \( H_2O \): Obtain the moles of hydrogen. 2. **Determine the simplest whole number ratio of the elements**: - Use the moles calculated in the previous step to find the ratio. 3. **Calculate the empirical formula**: - Convert the ratio into the simplest whole numbers. 4. **Find the molecular formula**: - Use the molar mass to find the molecular formula based on the empirical formula. #### Input Fields Enter the elements in the order presented in the question. Environmental formula = [ ] Molecular formula = [ ] Once all fields have been filled, click on the "Check & Submit Answer" button. For more details on the process, you can click the "Show Approach" button to see the detailed steps. **Check & Submit Answer** **Show Approach**
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