Sample Exercise 4: Calculation of molality and MolarityA solution is made by dissolving 4.35 g glucose (C6H₁2O6) in 25.0 mL of water at 25 °C.Calculate the (a) molality and (b) the Molarity of glucose in the solution. Water has adensity of 1.00 g/mL. The glucose solution has a density of 1.046 g/mL.Solution(a) Calculating molality requires that we know the mass of both componentsseparately. We then use the MM of the solute to get the moles of solute.mass H₂O: = 25.0 mL x 1.00 g25.0 mL xmLmoles glucose:1.00 g = 25.0 g H₂O MM C6H₁₂O6 = 180.16 g/mol4.35 g180.16 g mol-¹= 0.024145 mol C6H₁2 06molality glucose: 0.024145 mol = 0.966 m0.0250 kg H₂OMolarity glucose:(b) To get the Molarity of the glucose in the solution, we need to know the mass ofthe solution, then use the solution density to find the volume of the solution.mass of solution: mass H₂O + mass glucose = 25.0 g + 4.35 g = 29.35 gvolume of solution: 29.35 g x 1 mL = 28.06 mL of sol'n1.046 g= 0.860 M0.024145 mol0.02806 L sol'n

The objective is to find out the molality and molarity of glucose given glucose. water. density…

Sample Exercise 4: Calculation of molality and Molarity A solution is made by dissolving 4.35 g glucose (C6H₁2O6) in 25.0 mL of water at 25 °C. Calculate the (a) molality and (b) the Molarity of glucose in the solution. Water has a density of 1.00 g/mL. The glucose solution has a density of 1.046 g/mL. Solution (a) Calculating molality requires that we know the mass of both components separately. We then use the MM of the solute to get the moles of solute. mass H₂O: = 25.0 g H₂O MM C6H₁2O6 = 180.16 g/mol 25.0 mL x 1.00 g =

Sample Exercise 4: Calculation of molality and Molarity A solution is made by dissolving 4.35 g glucose (C6H₁2O6) in 25.0 mL of water at 25 °C. Calculate the (a) molality and (b) the Molarity of glucose in the solution. Water has a density of 1.00 g/mL. The glucose solution has a density of 1.046 g/mL. Solution (a) Calculating molality requires that we know the mass of both components separately. We then use the MM of the solute to get the moles of solute. mass H₂O: = 25.0 g H₂O MM C6H₁2O6 = 180.16 g/mol 25.0 mL x 1.00 g =

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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