># 3NikyQSales personnel for Skillings Distributors submit weekly reports listing the customer contactsmade during the week. A sample of 35 weekly reports showed a sample mean of 19.5 customercontacts per week. The population standard deviation was 5.2 Provide a 99% confidenceinterval for the population mean number of weekly customer contacts for the sales personnel.(17.777, 21.223)O (18.054, 20.946)(17.237, 21.763)(18.375, 20.625)O There is not enough information to provide the requested confidence interval.$4● ♫%5JA An AⓇMacBook Pro6&7W00PŒ-9zoom

It is given that Sample mean = 19.5Population standard deviation = 5.2Sample size = 35Confidence…

Answered: Sales personnel for Skillings…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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This assignment is worth 1 points. The extra point will be added to your overall course grade. For example: if you receive an 88% in the course you can receive up to 1 point giving you a new score of 89%. The following rubric will be used. 0.25 point for drawing the normal distribution curve with the mean value labeled on the curve and the appropriate area shaded. 0.25 point for determining the value of the standard deviation of the sample mean. 0.5 point for finding the correct probability. All work must be shown in order to receive any credit. Please upload your completed assignment here. The length of time taken on the SAT for a group of students is normally distributed with a mean of 2.5 hours and a standard deviation of 0.25 hours. A sample size of n = 60 is drawn randomly from the population. Find the probability that the sample mean is between two hours and three hours.
Consider a set of data in which the sample mean is 27 and the sample standard deviation is 6.2. Calculate the z-score given that x = 28.5. Round your answer to two decimal places. An
Suppose the population standard deviation is = 5, an SRS of n = 100 is obtained, and the confidence level is chosen to be 99.5%. The margin of error for estimating a mean is given by: a. 1.576. b. 1.165. c. 1.404. d. 1.223.
A researcher collects data that represents the average number of hours of sleep in the last two nights by 8 depressed patients and 9 non-depressed patients. The researcher is interested in whether the two groups reliably differ in the amount of sleep they get. Use Jamovi to calculate t-obt and the p value.
Given Samples A and B below Sample A: 2.0 Sample B: 4.3 2.8 4.5 O a. Calculate the mean and standard deviation for each sample. Sample A: XA = Sample B: XB = ; SB = Round to two decimal places if necessary b. Calculate the coefficient of variation for each sample. Sample A: CVA = ; SA = _% 4.2 4.2 4.3 4.0 Sample B: CVB Round to two decimal places if necessary c. Which sample is more variable? o Sample A Sample B Neither sample is more variable than the other 4.4 4.3 3.7 4.9 _% 3.6 2.6 2.8 2.2 2.3 4.1
After 84 students at a particular university take a psychological evaluation, the sample mean score on the test is calculated to be 117 with a standard deviation of 44. We are interested in testing whether or not the mean score of the students at this university is different than the published population average of 112. Calculate the value of the test statistic and then use that to determine the appropriate p-value. 0.5952 0.2976 0.1488 0.8512 1.7024 0.1488 0.0744
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