Salaries of 40 college graduates who took a statistics course in college have a mean, x, of $66,800. Assuming a standard deviation, o, of $17,038, construct a 99% confidence interval for estimating the population mean u. Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table, Click here to view page 2 of the standard normal distribution table. $_ <µ<$ _ (Round to the nearest integer as needed.)
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- Salaries of 42 college graduates who took a statistics course in college have a mean, x of $68,700. Assuming a standard deviation, o, of $18,646, construct a 90% confidence interval for estimating the population mean u. Click here o view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. $<μ<$ (Round to the nearest integer as needed.)Use the normal distribution of SAT critical reading scores for which the mean is 502 and the standard deviation is 116. Assume the variable x is normally distributed. (a) What percent of the SAT verbal scores are less than 550? (b) If 1000 SAT verbal scores are randomly selected, about how many would you expect to be greater than 525? Click to view page 1 of the standard normal table. Click to view page 2 of the standard normal table. (a) Approximately % of the SAT verbal scores are less than 550. (Round to two decimal places as needed.)Salaries of 39 college graduates who took a statistics course in college have a mean, x, of $64,800. Assuming a standard deviation, ơ, of $13,783, construct a 95% confidence interval for estimating the population mean µ. Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. ..... $>1> <µ< $ (Round to the nearest integer as needed.) %24
- Salaries of 43 college graduates who took a statistics course in college have a mean, x, of $66,900. Assuming a standard deviation, o, of $12,687, construct a 90% confidence interval for estimating the population mean u. Click here to viewat distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. SSalaries of 32 college graduates who took a statistics course in college have a mean, x, of $62,000. Assuming a standard deviation, 6, of $17,889, construct a 95% confidence interval for estimating the population mean µ. Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table.Salaries of 32 college graduates who took a statistics course in college have a mean, x, of $61,600. Assuming a standard deviation, o, of $11,936, construct a 99% confidence interval for estimating the population mean p. Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. ..... $ <µ < $ (Round to the nearest integer as needed.)According to recent UN figures, the annual gun homicide rate is 62.4 per one mil- lion residents in the US and 1.3 per one million residents in Britain. Compare the proportion of residents killed annually by guns using the (a) difference of propor- tions, (b) relative risk. Which measure is more useful for describing the strength of association? Why?Salaries of 38 college graduates who took a statistics course in college have a mean, x, of $65,900. Assuming a standard deviation, o, of $14,369, construct a 95% confidence interval for estimating the population mean μ. Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. <μ<$ (Round to the nearest integer as needed.)Salaries of 43 college graduates who took a statistics course in college have a mean, x, of $60,100. Assuming a standard deviation, o, of $14,135, construct a 95% confidence interval for estimating the population mean u. Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. $1 |<µ< $ (Round to the nearest integer as needed.)In a random sample of 36 criminals convicted of a certain crime, it was determined that the mean length of sentencing was 54 months, with a standard deviation of 13 months. Construct and interpret a 90% confidence interval for the mean length of sentencing for this crime. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). Click here to view the table of critical t-values. Select the correct choice below and fill in the answer boxes to complete your choice. (Use ascending order. Round to one decimal place as needed.) O A. There is a 90% probability that the mean length of sentencing for the crime is between and months. O B. We can be 90% confident that the mean length of sentencing for the crime is between and months. O C. 90% of the sentences for the crime are between and months.Salaries of 49 college graduates who took a statistics course in college have a mean, x, of $63,500. Assuming a standard deviation, o, of $14,619, construct a 90% confidence interval for estimating the population mean u. Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table Click here to view page 2 of the standard normal distribution table. $Use the normal distribution of SAT critical reading scores for which the mean is 502 and the standard deviation is 109. Assume the variable x is normally distributed. (a) What percent of the SAT verbal scores are less than 675? (b) If 1000 SAT verbal scores are randomly selected, about how many would you expect to be greater than 575? Click to view page 1 of the standard normal table. Click to view page 2 of the standard normal table. (a) Approximately % of the SAT verbal scores are less than 675. (Round to two decimal places as needed.) (b) You would expect that approximately whole number as needed.) SAT verbal scores would be greater than 575. 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