Salaries of 36 college graduates who took a statistics course in college have a mean, x, of $62,700. Assuming a standard deviation, o, of $16,957, construct a 95% confidence interval for estimating the population mean H. Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. $<µ<$ (Round to the nearest integer as needed.)
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Q: A data set includes 103 body temperatures of healthy adult humans having a mean of 98.5°F and a…
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Q: What is the confidence interval estimate of the population mean µμ? °F <H<°F (Round to three decimal…
A: It is given that Sample size n = 106 Sample mean M = 98.9 Sample SD s = 0.63 Confidence level = 99%
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A: From the provided information, Sample size (n) = 7 Sample mean (x̅) = 22 mpg Sample standard…
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A: As the population standard deviation is not known,we will use t distribution. Degrees of freedom are…
Q: A data set includes 103 body temperatures of healthy adult humans having a mean of 98.9°F and a…
A: Obtain the 99% confidence interval estimate of the mean body temperature of all healthy humans.…
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A: Given that Mean = M = 5.1 Standard deviation = SD = 0.5
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A: Given: n=34x=64300σ=1014190% confidence interval
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Q: Click here to view page 2 of the standard normal distribution table. What is the confidence interval…
A: It is given that Sample mean = 98.7Sample standard deviation = 0.66Sample size = 106Confidence level…
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Q: A data set includes 106 body temperatures of healthy adult humans having a mean of 98.9°F and a…
A: Given information: The sample size is n=106. The sample mean is x¯=98.9. The sample standard…
Q: A data set includes 103 body temperatures of healthy adult humans having a mean of 98.9°F and a…
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A: We have given that, n=103, X̄= 98.3 and standard deviation, s = 0.73 Confidence Interval Formula:…
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A: given data sample size (n) = 103sample mean ( x¯ ) = 98.3sample standard deviation (s) =0.7399% ci…
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A: Given, sample size(n)=47sample mean(x)=$68,600standard…
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Q: A data set includes 110 body temperatures of healthy adult humans having a mean of 98.0°F and a…
A: Here, the degrees of freedom is 109 (=n – 1). Using the Excel formula “=T.INV.2T(0.01,109)”, the…
Q: Salaries of 45 college graduates who took a statistics course in college have a mean, x, of $68,600.…
A: sample size(n)=45Mean()=68600standard deviation()=19010confidence level=90%
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A: Hypothesis to be tested: H0:μ≥24H1:μ<24
Q: Salaries of 49 college graduates who took a statistics course in college have a mean, x, of $67,200.…
A: Mean = 67200 Standard deviation = 11333 Sample size, n =49
Q: A data set includes 106 body temperatures of healthy adult humans having a mean of 98.9°F and a…
A: Given that:Mean=X=98.9Standard deviation=s=0.63n=106Since, n>30, so we can use the standard…
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Q: Salaries of 42 college graduates who took a statistics course in college have a mean, Click here to…
A: The sample size is n=42. The sample mean is x¯=$68700. The given population standard deviation is…
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- A data set includes 109 body temperatures of healthy adult humans having a mean of 98.3°F and a standard deviation of 0.54°F. Construct a 99% confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6°F as the mean body temperature? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean µ? (Round to three decimal places as needed.) What does this suggest about the use of 98.6°F as the mean body temperature? O A. This suggests that the mean body temperature could very possibly be 98.6°F. O B. This suggests that the mean body temperature is higher than 98.6°F. lower than 98.6°F O C. This suggests that the mean body temperatureSalaries of 47 college graduates who took a statistics course in college have a mean, x, of $62,900. Assuming a standard deviation, o, of $13,976, construct a 99% confidence interval for estimating the population mean u. Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table.A car company says that the mean gas mileage for its luxury sedan is at least 25 miles per gallon (mpg). You believe the claim is incorrect and find that a random sample of 6 cars has a mean gas mileage of 24 mpg and a standard deviation of 2 mpg. At a = 0.05, test the company's claim. Assume the population is normally distributed. Click here to view the t-distribution table. Click here to view page 1 of the normal table. Click here to view page 2 of the normal table. Which sampling distribution should be used and why? A. Use a normal sampling distribution because the population is normal, and o is known. B. Use a normal sampling distribution because n> 30. C. Use a t-sampling distribution because the population is normal, and o is known. D. Use a normal sampling distribution because the population is normal, and o is unknown. E. Use a t-sampling distribution because the population is normal, and o is unknown. O F. Use a t-sampling distribution because n 25 Ho: H#25 Ha: µ= 25 D. H : μ…A data set includes 106 body temperatures of healthy adult humans having a mean of 98.9°F and a standard deviation of 0.62°F. Construct a 99% confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6°F as the mean body temperature? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean µ? °F<μ<°F (Round to three decimal places as needed.) What does this suggest about the use of 98.6°F as the mean body temperature? O A. This suggests that the mean body temperature is lower than 98.6°F. B. This suggests that the mean body temperature is higher than 98.6°F. O C. This suggests that the mean body temperature could very possibly be 98.6°F. ... 1Need help with a review statistics question ASAPThe working life of a certain electrical equipment is normally distributed with a mean of 180 days and a standard deviation of 4 days. For each of the following questions, construct a normal distribution curve and provide the answer. About what percent of the products last between 176 and 184 days? About what percent of the products last between 180 and 184 days? For each of the following questions, use the standard normal table and provide the answer. About what percent of the products last 172 or less days? About what percent of the products last 184 or more days?This assignment is worth 1 points. The extra point will be added to your overall course grade. For example: if you receive an 88% in the course you can receive up to 1 point giving you a new score of 89%. The following rubric will be used. 0.25 point for drawing the normal distribution curve with the mean value labeled on the curve and the appropriate area shaded. 0.25 point for determining the value of the standard deviation of the sample mean. 0.5 point for finding the correct probability. All work must be shown in order to receive any credit. Please upload your completed assignment here. The length of time taken on the SAT for a group of students is normally distributed with a mean of 2.5 hours and a standard deviation of 0.25 hours. A sample size of n = 60 is drawn randomly from the population. Find the probability that the sample mean is between two hours and three hours.Salaries of 32 college graduates who took a statistics course in college have a mean, x, of $62,000. Assuming a standard deviation, 6, of $17,889, construct a 95% confidence interval for estimating the population mean µ. Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table.A data set includes 109 body temperatures of healthy adult humans having a mean of 98.2°F and a standard deviation of 0.62°F. Construct a 99% confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6°F as the mean body temperature? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean µ? °F1 (Round to three decimal places as needed.)A data set includes 103 body temperatures of healthy adult humans having a mean of 98.5°F and a standard deviation of 0.61°F. Construct a 99% confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6°F as the mean body temperature? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table, What is the confidence interval estimate of the population mean µ? O'FSalaries of 49 college graduates who took a statistics course in college have a mean, x, of $63,500. Assuming a standard deviation, o, of $14,619, construct a 90% confidence interval for estimating the population mean u. Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table Click here to view page 2 of the standard normal distribution table. $A data set includes 103 body temperatures of healthy adult humans having a mean of 98.5°F and a standard deviation of 0.61°F. Construct a 99% confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6°F as the mean body temperature? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean µ? (Round to three decimal places as needed.) What does this suggest about the use of 98.6°F as the mean body temperature? O A. This suggests that the mean body temperature is significantly higher than 98.6°F. O B. This suggests that the mean body temperature could very possibly be 98.6°F. OC. 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