Salaries of 33 college graduates who took a statistics course in college have a​ mean, x​, of $65,400. Assuming a standard​ deviation, σ​, of ​$19,612​, construct a 99​% confidence interval for estimating the population mean μ.

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Salaries of 33 college graduates who took a statistics course in college have a​ mean, x​, of $65,400. Assuming a standard​ deviation, σ​, of ​$19,612​, construct a 99​% confidence interval for estimating the population mean μ.

Salaries of 33 college graduates who took a statistics course in college have a mean, x, of $65,400. Assuming a standard deviation, o, of $19,612,
construct a 99% confidence interval for estimating the population mean μ.
Click here to view a t distribution table.
Click here to view page 1 of the standard normal distribution table.8
Click here to view page 2 of the standard normal distribution table.Ⓡ
<μ<s
(Round to the nearest integer as needed.)
Transcribed Image Text:Salaries of 33 college graduates who took a statistics course in college have a mean, x, of $65,400. Assuming a standard deviation, o, of $19,612, construct a 99% confidence interval for estimating the population mean μ. Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table.8 Click here to view page 2 of the standard normal distribution table.Ⓡ <μ<s (Round to the nearest integer as needed.)
Expert Solution
Step 1: Introduce the given information

According to the given information,

Sample size, n = 33

Sample mean, x with bar on top = 65400

Population standard deviation, σ = 19612

Confidence level, C = 99% = 0.99

Since, population standard deviation (σ) is known and sample size (n) greater than 30. So we use standard normal distribution.

Using formula,

C o n f i d e n c e space i n t e r v a l equals x with bar on top plus-or-minus fraction numerator Z subscript c cross times sigma over denominator square root of n end fraction

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