Sal G(x) = (x³ + [-1, 3] +8 2 X² this type of question "On the interval of" [-1,3]. " I'm stuck over the fraction parts. I guess I cannot use I cannot use decimals, then multiply by old denominator : the trick wint work? I can do these problems withoutt fractions easily. My previous work work! 3 9(-1) = 6 (-1)³ +8 -1² the Averge is Rate of Change 9(3) = -6(3)³ + 8 -3² - 6 (-8). (14) ²X 91-1) = (-14) (-1₁-14) 9 1-14661 + 6 (27) (-4) 19/3)= (-1446 13-1466 9-162+8 if(b)-f(a) 9
Sal G(x) = (x³ + [-1, 3] +8 2 X² this type of question "On the interval of" [-1,3]. " I'm stuck over the fraction parts. I guess I cannot use I cannot use decimals, then multiply by old denominator : the trick wint work? I can do these problems withoutt fractions easily. My previous work work! 3 9(-1) = 6 (-1)³ +8 -1² the Averge is Rate of Change 9(3) = -6(3)³ + 8 -3² - 6 (-8). (14) ²X 91-1) = (-14) (-1₁-14) 9 1-14661 + 6 (27) (-4) 19/3)= (-1446 13-1466 9-162+8 if(b)-f(a) 9
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
To better map out everything — I added two pictures. I am having trouble at the basic fraction parts. Worked on this problem for over an hour.. I’m sry for the unclear question before. Tearing my hair out.
Ty again I am sorry
![2
H
I can do these problems.
fractions easily.
My previous tork work!
g (-1) = 6 (-1) ³ + 8/1²/2
+/
2
= 6 + ( 8 ) ・ (14) | X 9 (-1) = (-14)
(-1₁-14)
9(3) = -6(3)3 +8
-8
-3²
+ (6-(27) + (-39) 2014
9-162+8
9
9
-1,458 (8)
q
+(2). /
1,458 +8
9
-1,466
Ксс
-1,466-(-14)
9
1466+14.9.
917
3-(-1) = 4
KCC
3355
9
without
9/3) = (-1466)
q
3,-1466
Ff(b)-Fla)
ba
*
-1466+ 126
9
7
355057
*
(Rate of)
Change!
355
1340
4 (4)
4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd77efdd2-3627-4e60-9cc5-269368d346aa%2Ff446b2de-216e-441d-abd5-b30523060be3%2F50dzjqv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2
H
I can do these problems.
fractions easily.
My previous tork work!
g (-1) = 6 (-1) ³ + 8/1²/2
+/
2
= 6 + ( 8 ) ・ (14) | X 9 (-1) = (-14)
(-1₁-14)
9(3) = -6(3)3 +8
-8
-3²
+ (6-(27) + (-39) 2014
9-162+8
9
9
-1,458 (8)
q
+(2). /
1,458 +8
9
-1,466
Ксс
-1,466-(-14)
9
1466+14.9.
917
3-(-1) = 4
KCC
3355
9
without
9/3) = (-1466)
q
3,-1466
Ff(b)-Fla)
ba
*
-1466+ 126
9
7
355057
*
(Rate of)
Change!
355
1340
4 (4)
4
![Saw) -
G(x) = (x3 + 8 [-1₁3]
X²
this type of question
"On the interval of" [-1,3].
"
I'm stuck over the fraction parts.
I guess I cannot use decimals,
then multiply by old denominator :
the trick win't work?
I can do these problems withouth
fractions easily.
the Averge
is Rate of Change
My previous twork work!
3
9(-1) = 6 (-1)³ + 8
-12
- 6 + (-8) • (1²) ²× 9 (-1) = (-14)
X
2
(-1₁-14)
9(3) = -6(3)³ + 8
-81
-3²
+ (6 (27) + (-29) 2014
V
9-162+8
9
176
9
* 9/3) = / -14461
q
3, -1466
Ff(b) f(a)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd77efdd2-3627-4e60-9cc5-269368d346aa%2Ff446b2de-216e-441d-abd5-b30523060be3%2F55o43q_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Saw) -
G(x) = (x3 + 8 [-1₁3]
X²
this type of question
"On the interval of" [-1,3].
"
I'm stuck over the fraction parts.
I guess I cannot use decimals,
then multiply by old denominator :
the trick win't work?
I can do these problems withouth
fractions easily.
the Averge
is Rate of Change
My previous twork work!
3
9(-1) = 6 (-1)³ + 8
-12
- 6 + (-8) • (1²) ²× 9 (-1) = (-14)
X
2
(-1₁-14)
9(3) = -6(3)³ + 8
-81
-3²
+ (6 (27) + (-29) 2014
V
9-162+8
9
176
9
* 9/3) = / -14461
q
3, -1466
Ff(b) f(a)
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