S(7x³-5 √√x + 18 √x x3 + x−40 ) dx

Q: (2x)√2x + 1 dx

A:

Q: S (3×÷12x -15)% 2dx +12メ -15)2

A: Here we have to find the value of     ∫ 2dx/(3x2+12x-15)

Q: (4) √x³√x² +1dx

A: We solve the given problem using the substitution method.

Q: 44. (-x + 4x – 5) dx -2

A:

Q: x dx Evaluate (4a² +9x?) 2

A:

Q: 3 2. x1 + x² dx

A: Definate integration

Q: √√√√5 ²x dx - X A. -2√5-x + C C. √5-x+C B. D. √5-x +C -√5-x+C

A:

Q: alculate the remainder when (2x³ = x² = 5x + 7) = (x - 2) - Paragraph v В T A/ +

A: Given query is to find the remainder.

Q: J ** +3x³ + 2x² + 1 x² + 3x + 2 dx; use division.

A:

Q: ∫(7x3 + 19)4 21x2 dx

A:

Q: -8x? + 16x + 8 dx (x – 1)2(x² + 1)

A: We will solve the problem

Q: 7- Find fx³√3 - 2x² dx

A:

Q: (i) ,(8x³ – 9x² + 8x + 9)dx |

A: SINCE YOU HAVE ASKED MULTIPLE QUESTIONS IN SINGLE REQUEST, WE WILL BE ANSWERING ONLY THE FIRST…

Q: 2 4-3x² + 5x + 2 x dx =

A: ∫24-3x2+5x+2xdx

Q: O/ Eve luate the fo llowing x² V 4 -9x² dx (2) x²-4X+13

A:

Q: L² (3x² 1 − 2x + 1) dx

A: Solve the definite integration

Q: x5 dx 3 (36x2 + 1)7

A: I am attaching image so that you understand each and every step.

Q: dx |x-1|

A: To evaluate the following integral.

Q: d [(5 – 3x – 4x³)5(3x – 4)] dx

A: Derivative using product rule.

Q: S 2x/6-7x dx 6.

A: Using substitution method.

Q: 3√3 dx √3 x² √√x² +9 2

A:

Q: |x + 2| dx -4

A:

Q: 6​[2−6​(−8x−5​)]=288x+192

A:

Q: √x√√7-x² d dx - S

A:

Q: Evaluate ·S dx 2 ²√x²-9

A:

Q: S7=1−1/√2+1/2−12/√2+14−14/√2+1/8.

A: Given:

Q: (x'.3 + 7x25) dx + 7x²5

A: Given, ∫x1.3+7x2.5dx  We have to find the integral.

Q: d 4х +11 15. In((x + 1)(2x + 9)) dx (x + 1)(2x + 9)

A: Given:ddxlnx+12x+9

Q: d [(9p5+ 16p-8) 15] = 15 (9p³ + 16p-8) ¹4. (45p¹+16) dp True False

A:

Q: 8. Evaluate (3x² +6x² – 4x +1)dx.

A:

Q: ( 2x2 +3 (x²+1 )? 구. dx

A: From the given problem:   I=∫ 2x2+3x2+12dx ....(1)   Now take the partial fraction:…