The beam shown in Fig. P.13.1 is simply supported symmetrically at two points 2 m from eachend and carries a uniformly distributed load of 5 kN/m together with two concentrated loads of2 kN each at its free ends. Calculate the deflection at the mid-span point and at its free ends usingthe method of double integration. El = 43×101² Nmm².Ans. 3.6 mm (downwards), 2.0 mm (upwards).2 kN2 kNw = 5 kN/mFIGURE P.13.12 m8 m2 m

Data Given: EI = 43 x 1012 Nmm2 Asked: Deflection at mid span and at free end using the method of…

Answered: s. 3.6 mm (downwards), 2.0 mm…

Engineering

Civil Engineering

s. 3.6 mm (downwards), 2.0 mm (upwards). EN 2 kN w = 5 kN/m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

The beam shown in Fig. P.13.1 is simply supported symmetrically at two points 2 m from each
end and carries a uniformly distributed load of 5 kN/m together with two concentrated loads of
2 kN each at its free ends. Calculate the deflection at the mid-span point and at its free ends using
the method of double integration. El = 43×101² Nmm².
Ans. 3.6 mm (downwards), 2.0 mm (upwards).
2 kN
2 kN
w = 5 kN/m
FIGURE P.13.1
2 m
8 m
2 m

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Step 3 Calculations with the help of double integration method

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