с. 2.50 х 10 2 МНСIO, OJOH"] = 2.50 x 10-² M, H,O* = 2.50 x 10-2 M OJOH"] = 4.00 x 10-18 M, H,O* = 2.50 x 10-2 M o JOH"] = 2.50 x 10-² M, H3O+ = 4.00 × 10-18 M o JOH") = 4.00 x 10-18 M, H,O* = 4.00 x 10-18 M 4.00 x 10-13 М d. 0.860 M НCI o[OH"] = 0.860 M, H3O+ = 0.860 M O[OH¯] = 1.16 M, H3O* = 0.860 M 0Он- 1.16 х 10 14 М, |н,0*] %-D 0.860 M M, H3O*] оон — 0.86о м, |н,о+ — 1.16 х 1014 М
с. 2.50 х 10 2 МНСIO, OJOH"] = 2.50 x 10-² M, H,O* = 2.50 x 10-2 M OJOH"] = 4.00 x 10-18 M, H,O* = 2.50 x 10-2 M o JOH"] = 2.50 x 10-² M, H3O+ = 4.00 × 10-18 M o JOH") = 4.00 x 10-18 M, H,O* = 4.00 x 10-18 M 4.00 x 10-13 М d. 0.860 M НCI o[OH"] = 0.860 M, H3O+ = 0.860 M O[OH¯] = 1.16 M, H3O* = 0.860 M 0Он- 1.16 х 10 14 М, |н,0*] %-D 0.860 M M, H3O*] оон — 0.86о м, |н,о+ — 1.16 х 1014 М
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![с. 2.50 х 10 2 МНСIO,
OJOH"] = 2.50 x 10-² M, H,O* = 2.50 x 10-2 M
OJOH"] = 4.00 x 10-18 M, H,O* = 2.50 x 10-2 M
o JOH"] = 2.50 x 10-² M, H3O+ = 4.00 × 10-18 M
o JOH") = 4.00 x 10-18 M, H,O* = 4.00 x 10-18 M
4.00 x 10-13 М
d. 0.860 M НCI
o[OH"] = 0.860 M, H3O+ = 0.860 M
O[OH¯] = 1.16 M, H3O* = 0.860 M
0Он- 1.16 х 10 14 М, |н,0*] %-D 0.860 M
M, H3O*]
оон — 0.86о м, |н,о+ — 1.16 х 1014 М](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F17b7c333-bc09-4ff0-9d99-0fb21b9f9655%2Fa7ba09ff-49d4-4556-a80d-67484fca6b79%2Fjh4l1a.png&w=3840&q=75)
Transcribed Image Text:с. 2.50 х 10 2 МНСIO,
OJOH"] = 2.50 x 10-² M, H,O* = 2.50 x 10-2 M
OJOH"] = 4.00 x 10-18 M, H,O* = 2.50 x 10-2 M
o JOH"] = 2.50 x 10-² M, H3O+ = 4.00 × 10-18 M
o JOH") = 4.00 x 10-18 M, H,O* = 4.00 x 10-18 M
4.00 x 10-13 М
d. 0.860 M НCI
o[OH"] = 0.860 M, H3O+ = 0.860 M
O[OH¯] = 1.16 M, H3O* = 0.860 M
0Он- 1.16 х 10 14 М, |н,0*] %-D 0.860 M
M, H3O*]
оон — 0.86о м, |н,о+ — 1.16 х 1014 М
Expert Solution
Step 1
c) HClO4 is a strong acid which dissociates completely as per the reaction
HClO4 + H2O --------> H3O+ + ClO4-
Hence the concentration of H3O+ ions = [H3O+ ] = concentration of HClO4 = 2.50 X 10-2 M
Since pOH = 14 - pH
=> -log[OH-] = 14 - (-log[H3O+ ] )
Hence substituting the values we get
=> -log[OH-] = 14 + log(2.50 X 10-2 ) = 12.4
=> [OH-] = concentration of OH- ions = 10-12.4 = 4 X 10-13 M
Hence the answer is option 2.
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