S² Sxx-6-dx 2 (x²+2 + = ²3 ) dx X-3 Sx x²-x-6 Sx (x+2)(x-3) A X=-2 = [2ln lx+21+31n/x-31] 21n/2+21+ 3 lul 2-31]-[2lul-1+21+ 31u1-1-31] B X=3 5X (X+2)(x-3) A + X+2 = = 5(-2) (-2+2)(-2-2 5 (3) (3+2)(3-3) 2 X+2 3 X-
S² Sxx-6-dx 2 (x²+2 + = ²3 ) dx X-3 Sx x²-x-6 Sx (x+2)(x-3) A X=-2 = [2ln lx+21+31n/x-31] 21n/2+21+ 3 lul 2-31]-[2lul-1+21+ 31u1-1-31] B X=3 5X (X+2)(x-3) A + X+2 = = 5(-2) (-2+2)(-2-2 5 (3) (3+2)(3-3) 2 X+2 3 X-
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Related questions
Question
How do i simplify the ln equation are the bottom. The answer should be -ln4
![8.5.29)
Sx
-1x²-x-6 dx
S²
[(-)dx
X-3
7
Sx
x²-x-6
SX
(X+2)(x-3)
= [2lmlx+21+ 3/n/x-31] | ²
= [2ln | 2+21+ 3 lul 2-31]-[2lul-1+21 +31 ul-1-31]
B
X=3
5 X
(X+2)(x-3)
A
X + 2
A
X=-2 (-2+2)(-2-3)
=
- B
5(-2)
5(3)
(3+2)(3-3)
2
x+2
(x-3)
=
:
15
S
3
X-3
-10
-5
=2=
2
X+2
= 3 = 3
X-3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F25b167f9-3118-479d-a9fb-f8c446c41f1a%2F06974c67-5974-467e-9299-8f702f4fabb7%2F41av5n5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:8.5.29)
Sx
-1x²-x-6 dx
S²
[(-)dx
X-3
7
Sx
x²-x-6
SX
(X+2)(x-3)
= [2lmlx+21+ 3/n/x-31] | ²
= [2ln | 2+21+ 3 lul 2-31]-[2lul-1+21 +31 ul-1-31]
B
X=3
5 X
(X+2)(x-3)
A
X + 2
A
X=-2 (-2+2)(-2-3)
=
- B
5(-2)
5(3)
(3+2)(3-3)
2
x+2
(x-3)
=
:
15
S
3
X-3
-10
-5
=2=
2
X+2
= 3 = 3
X-3
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