lay's Reaction: NaHCO3 (s) + HCI (aq) → NaCI (aq) + H2O () + CO2 (g)Note: the CO2 will evaporate away as a gas and you will use the hot plate to boil awaythe water as a gas, leaving a solid sodium chloride as a white powder in your beaker.Data table:Mass to determine:Trial 1Trial 21) Mass of beaker and boiling chipsBefore52.96° 50-13Reaction2) Mass of beaker, NaHCO3, and boiling chipsS3-S5 S0-82°3) Mass of just the NaHCO3(HINT: line 2 minus line 1)0-690-5953-89 9 50-80 9•6704) Mass of beaker, NaCl, boiling chipsAfter5) Mass of just the NaCl, a.k.a, your "actual yield".93 9(HINT: line 4 minus line 1)Reaction 08Calculations: Show all work for calculations below.A. Molar mass determination (show your units):NaciNaHCOsB. Theoretical Yield of NaCl for both trials:Trial 1:mot NaHCO3mot Nacimol NaHCO3mot Nactactual yieldPercent yield (rial I) =theoretical yield= 001 xTrial 2:EOONDN 10uNaNco3Percent yield (arial 2) -theoretical yield- 001 xAnalysis of Results:Briefly suggest two possible sources of error in this experiment (human error is not is notan acceptable "source of error"). You should focus on actual experimental events thatcould have caused experimental error in the data. Hint: think about the heating step, howwould your results be impacted if you over-heated or under-heated the salty-sludge?1.2.

It is given that sodium bicarbonate (NaHCO3) is reacting with hydrochloric acid (HCl) to form sodium…

's Reaction: NaHCO3 (s) + HCI (aq) → NaCI (aq) + H2O () + CO2 (g) Note: the CO2 will evaporate away as a gas and you will use the hot plate to boil away the water as a gas, leaving a solid sodium chloride as a white powder in your beaker. Data table: Mass to determine: Trial 1 Trial 2 1) Mass of beaker and boiling chips Before 52.96 50-13 Reaction 2) Mass of beaker, NaHCO3, and boiling chips 3-55 50-829 6. 3) Mass of just the NaHCO3 (HINT: line 2 minus line 1) 0-59 0-69 4) Mass of beaker, NaCl, boiling chips 53-89 9 50-80 9 After Reaction 5) Mass of just the NaCl, a.k.a, your "actual yield" |,93 9 (HINT: line 4 minus line 1) •67 6,

's Reaction: NaHCO3 (s) + HCI (aq) → NaCI (aq) + H2O () + CO2 (g) Note: the CO2 will evaporate away as a gas and you will use the hot plate to boil away the water as a gas, leaving a solid sodium chloride as a white powder in your beaker. Data table: Mass to determine: Trial 1 Trial 2 1) Mass of beaker and boiling chips Before 52.96 50-13 Reaction 2) Mass of beaker, NaHCO3, and boiling chips 3-55 50-829 6. 3) Mass of just the NaHCO3 (HINT: line 2 minus line 1) 0-59 0-69 4) Mass of beaker, NaCl, boiling chips 53-89 9 50-80 9 After Reaction 5) Mass of just the NaCl, a.k.a, your "actual yield" |,93 9 (HINT: line 4 minus line 1) •67 6,

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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