Thermodynamics, please help and show all work please. **Thermodynamics: Refrigerant 134a Compression Analysis****Problem Statement:**Refrigerant 134a is compressed from 4 bar, saturated vapor, to 10 bar, 90°C in a compressor operating at steady state. The mass flow rate of refrigerant entering the compressor is 7 kg/min, and the power input is 10.85 kW. Kinetic and potential energy effects can be neglected.**Objective:**(a) Determine the rate of heat transfer for the compressor, in kW. Note that heat transfer is positive going into the compressor.(b) If the heat transfer occurs at an average surface temperature of 50°C, determine the rate of entropy production, in kW/K.(c) Determine the rate of entropy production, in kW/K, for an enlarged control volume that includes the compressor and its immediate surroundings such that the heat transfer occurs at 300 K.**Solution Steps:****Part A**- **Determine the rate of heat transfer for the compressor, in kW.** \( \dot{Q}_{cv} = \quad \_\_\_\_ \text{kW} \)Please calculate this using the relevant thermodynamic relationships and provided data.---**Explanation of Given Data and Equations:**- Refrigerant 134a data - Initial state: 4 bar, saturated vapor - Final state: 10 bar, 90°C - Mass flow rate: 7 kg/min (convert to kg/s) - Power input: 10.85 kW- Energy balance equation for steady state (neglecting kinetic and potential energy changes): \[ \dot{Q} = \dot{m} (h_2 - h_1) + \dot{W} \]**Graphical Elements:**- **No graphs or diagrams** are provided in this problem statement.---This detailed breakdown ensures an organized approach for students learning how to apply thermodynamic principles to real-life engineering problems.

R-134aP1=4 barP2=10 barT2=90°Cm˙=7kg/minPin=10.85kW˙ To-Find:- Qcv˙=?

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Engineering

Mechanical Engineering

s, please help

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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