S For x1/2 x−x³ dx and using the substitution u=x1/2, the resulting integral takes the form:

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S
For
x1/2
√x-x³
S
S
U
-dx and using the substitution
du
-du
4u
√4-(22) 2
4u
4-u2
u=x 1/2, the resulting integral takes the form:
Transcribed Image Text:S For x1/2 √x-x³ S S U -dx and using the substitution du -du 4u √4-(22) 2 4u 4-u2 u=x 1/2, the resulting integral takes the form:
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