S Apply Trigonometric Ratios Note x b aaps.schoology.com/common-assessment-delivery/start/4764986925?action%3Donresume&submissionid%-D457403232 Applying Trigonometric Ratios (#2 Geometry/AC) - Independent Match the ratio of side lengths to its corresponding angle measure. adjacent leg ÷ hypotenuse = 0.139 opposite leg adjacent leg 0.249 opposite leg hypotenuse = 0.469 adjacent leg hypotenuse = 0.682 opposite leg hypotenuse = 0.848 : 14° :: 28° :: 47° : 58° : 82

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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How do I solve this to match the ratio of side lengths to corresponding angles measures ?
41
5.
S Apply Trigonometric Ratios Note x +
a aaps.schoology.com/common-assessment-delivery/start/4764986925?action3Donresume&submissionld=457403232
Applying Trigonometric Ratios (#2 Geometry/AC) - Independent
Match the ratio of side lengths to its corresponding angle measure.
adjacent leg ÷ hypotenuse = 0.139
opposite leg adjacent leg = 0.249
opposite leg hypotenuse = 0.469
adjacent leg + hypotenuse = 0.682
opposite leg hypotenuse = 0.848
:: 14°
:: 28°
:: 47°
:: 58°
: 82°
2
3.
6 7
Transcribed Image Text:41 5. S Apply Trigonometric Ratios Note x + a aaps.schoology.com/common-assessment-delivery/start/4764986925?action3Donresume&submissionld=457403232 Applying Trigonometric Ratios (#2 Geometry/AC) - Independent Match the ratio of side lengths to its corresponding angle measure. adjacent leg ÷ hypotenuse = 0.139 opposite leg adjacent leg = 0.249 opposite leg hypotenuse = 0.469 adjacent leg + hypotenuse = 0.682 opposite leg hypotenuse = 0.848 :: 14° :: 28° :: 47° :: 58° : 82° 2 3. 6 7
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