с app.101edu.co YouTube TING AMOUNT Maps X Aktiv Chemistry Welcome to MyTCC 403-Forbidden: Ac..... 102.94 X 89.6 ADD FACTOR *( ) go₂ b Home | bartleby What quantity in moles of MnO are produced when 4.30 kg of oxygen gas completely reacts according to the balanced chemical reaction: 6.022 x 10 100 g Mn Question 49 of 50 2 Mn(s) + 30-(g) - 9.22 x 10⁰ 0.001 g MnO₂ 0.1 X 3 32.00 kg O₂ ANDINER 0.0896 1000 Your Sets | Quizlet 2 MnO,(s) 0.01 mol O: 10 4.30 mol Mn 1 RESET 2 54.94 mol MnO₂ 2 X +
с app.101edu.co YouTube TING AMOUNT Maps X Aktiv Chemistry Welcome to MyTCC 403-Forbidden: Ac..... 102.94 X 89.6 ADD FACTOR *( ) go₂ b Home | bartleby What quantity in moles of MnO are produced when 4.30 kg of oxygen gas completely reacts according to the balanced chemical reaction: 6.022 x 10 100 g Mn Question 49 of 50 2 Mn(s) + 30-(g) - 9.22 x 10⁰ 0.001 g MnO₂ 0.1 X 3 32.00 kg O₂ ANDINER 0.0896 1000 Your Sets | Quizlet 2 MnO,(s) 0.01 mol O: 10 4.30 mol Mn 1 RESET 2 54.94 mol MnO₂ 2 X +
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![**Chemistry Stoichiometry Problem**
**Question 49 of 50**
**Problem Statement:**
What quantity in moles of \( \text{MnO}_2 \) are produced when 4.30 kg of oxygen gas completely reacts according to the balanced chemical reaction:
\[ 2 \text{MnS} + 3 \text{O}_2(g) \rightarrow 2 \text{MnO}_2(s) \]
**Equation Setup:**
- **Balanced Reaction Equation:**
- \( 2 \text{MnS}(s) + 3 \text{O}_2(g) \rightarrow 2 \text{MnO}_2(s) \)
- **Starting Amount:**
- 4.30 kg of \( \text{O}_2 \)
- **Conversion Factors and Constants:**
- Molar Mass of \( \text{O}_2 \): 32.00 g/mol
- Conversion: kg to g = 1000 g/kg
- Moles of \( \text{O}_2 \): Required calculation
- Ratio from balanced reaction: \( \frac{2 \text{MnO}_2}{3 \text{O}_2} \)
**Buttons/Values for Calculation:**
- Values: 89.6, 6.022 x 10\(^2\), 9.22 x 10\(^3\), 32.00, 0.01, 4.30, 54.94, 102.94, 1000
- Conversions: kg \( \text{O}_2 \) to g \( \text{O}_2 \), g \( \text{Mn} \), mol \( \text{Mn} \), mol \( \text{MnO}_2 \)
**Procedure:**
1. Convert 4.30 kg of \( \text{O}_2 \) to grams.
2. Calculate moles of \( \text{O}_2 \) using its molar mass.
3. Use the stoichiometric ratio to find moles of \( \text{MnO}_2 \) produced.
This scaffold helps illustrate the conversion steps necessary for stoichiometry calculations in chemical reactions. It aids in understanding the relationship between reactants and products within a given chemical equation.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0406c5f8-494f-428b-ae59-e78691671853%2F1a928688-3051-4c65-950c-ffb8d3637e20%2Fdd2vzi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Chemistry Stoichiometry Problem**
**Question 49 of 50**
**Problem Statement:**
What quantity in moles of \( \text{MnO}_2 \) are produced when 4.30 kg of oxygen gas completely reacts according to the balanced chemical reaction:
\[ 2 \text{MnS} + 3 \text{O}_2(g) \rightarrow 2 \text{MnO}_2(s) \]
**Equation Setup:**
- **Balanced Reaction Equation:**
- \( 2 \text{MnS}(s) + 3 \text{O}_2(g) \rightarrow 2 \text{MnO}_2(s) \)
- **Starting Amount:**
- 4.30 kg of \( \text{O}_2 \)
- **Conversion Factors and Constants:**
- Molar Mass of \( \text{O}_2 \): 32.00 g/mol
- Conversion: kg to g = 1000 g/kg
- Moles of \( \text{O}_2 \): Required calculation
- Ratio from balanced reaction: \( \frac{2 \text{MnO}_2}{3 \text{O}_2} \)
**Buttons/Values for Calculation:**
- Values: 89.6, 6.022 x 10\(^2\), 9.22 x 10\(^3\), 32.00, 0.01, 4.30, 54.94, 102.94, 1000
- Conversions: kg \( \text{O}_2 \) to g \( \text{O}_2 \), g \( \text{Mn} \), mol \( \text{Mn} \), mol \( \text{MnO}_2 \)
**Procedure:**
1. Convert 4.30 kg of \( \text{O}_2 \) to grams.
2. Calculate moles of \( \text{O}_2 \) using its molar mass.
3. Use the stoichiometric ratio to find moles of \( \text{MnO}_2 \) produced.
This scaffold helps illustrate the conversion steps necessary for stoichiometry calculations in chemical reactions. It aids in understanding the relationship between reactants and products within a given chemical equation.
Expert Solution
Step 1
How many moles of MnOs are produced when 4.30 kg of oxygen gas completely reacts according to the balanced chemical reaction:
2 Mn(s) + 3 O2(g) 2 MnO (s)
Step by step
Solved in 2 steps
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