·S (a) tan-¹(x) + C (d) tan-¹(2x) + C (g) tan-¹ (r) + C (i) None of the above 1 1+4x2 15. Evaluate da 16. Evaluate ² sin(2x) dx (c) r² - a cos(2x) (b) 2 tan-¹(x) + C (e) 2 tan-¹(2x) + C (h) 2 tan-¹ (x) + C -1 1 1 (a) — ½a² cos(2x) + ½a sin(2x) + — cos(2x) + C 1 sin(2x) -cos (2x) + C (e) -2x² cos(2x) + 8x sin(2x) + 16 cos(2x) + C (g) 2r² cos(2x) - 8x sin (2x) - 16 cos(2x) + C (i) None of the above 1 (b) − a² sin(2x) + (c)-tan-¹(x) + C (f) tan-¹(2x) + C (i)tan-¹ (x) + C 1 x cos(2x)+sin(2x) + C 1 - - (d) r² sin(2x) — a cos(2x) — — sin(2x) + C (f)-2x² sin(2x) + 8x cos(2x) + 16 sin(2x) + C (h) 2x² sin(2x) - 8x cos(2x) - 16 sin(2x) + C
·S (a) tan-¹(x) + C (d) tan-¹(2x) + C (g) tan-¹ (r) + C (i) None of the above 1 1+4x2 15. Evaluate da 16. Evaluate ² sin(2x) dx (c) r² - a cos(2x) (b) 2 tan-¹(x) + C (e) 2 tan-¹(2x) + C (h) 2 tan-¹ (x) + C -1 1 1 (a) — ½a² cos(2x) + ½a sin(2x) + — cos(2x) + C 1 sin(2x) -cos (2x) + C (e) -2x² cos(2x) + 8x sin(2x) + 16 cos(2x) + C (g) 2r² cos(2x) - 8x sin (2x) - 16 cos(2x) + C (i) None of the above 1 (b) − a² sin(2x) + (c)-tan-¹(x) + C (f) tan-¹(2x) + C (i)tan-¹ (x) + C 1 x cos(2x)+sin(2x) + C 1 - - (d) r² sin(2x) — a cos(2x) — — sin(2x) + C (f)-2x² sin(2x) + 8x cos(2x) + 16 sin(2x) + C (h) 2x² sin(2x) - 8x cos(2x) - 16 sin(2x) + C
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
15 & 16 solve all please
Transcribed Image Text:·l
(a) tan-¹(x) + C
(d) tan-¹(2x) + C
(g) tan-¹(x) + C
(j) None of the above
1
1+4x2
15. Evaluate
da
16. Evaluate ² sin(2x) dx
(b) 2 tan-¹(x) + C
(e) 2 tan-¹(2x) + C
(h) 2 tan-¹ (x) + C
-1
1
(a) -2² cos(2x) + sin(2x)+cos(2x) + C
² cos(2x) sin(2x)-cos(2x) + C
- a
(e) -2x² cos(2x) + 8x sin(2x) + 16 cos(2x) + C
(g) 2x² cos(2x) - 8x sin (2x) - 16 cos (2x) + C
(i) None of the above
(c)-tan-¹(x) + C
(f) tan-¹(2x) + C
(i)tan-¹ (x) + C
1
1
(b) −z² sin(2x) + ½æ cos(2x) + = sin(2x) + C
1
(d) ² sin(2x) — a cos(2x) ——sin(2x) + C
-
(f) -2x² sin(2x) + 8x cos(2x) + 16 sin(2x) + C
(h) 2x2 sin(2x) - 8x cos(2x) - 16 sin(2x) + C
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