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(s) A random sample of 120 observations is selected from a binomial population with unknown probability of success p. The computed value of p is 0.63 (1) Test Ho: p= 0.65 against H:p> 0.65. Use a = 0.05. test statistic z critical z score The final conclusion is OA. We can reject the null hypothesis that p= 0.65 and accept that p > 0.65 OB. There is not sufficient evidence to reject the null hypothesis that p=0.65 (2) Test Ho: p=0.65 against H, :p<0.65. Use a = 0.01 test statistic = critical z score The final conclusion is OA. There is not sufficient evidence to reject the null hypothesis that p=0.65 OB. We can reject the null hypothesis that p= 0.65 and accept that p < 0.65. (3) Test Ho: p=0.6 against He: p0.6. Use a = 0.05 test statistic positive critical score negative critical score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p=0.6. B. We can reject the null hypothesis that p=0.6 and accept that p = 0.6 4

(s) A random sample of 120 observations is selected from a binomial population with unknown probability of success p. The computed value of p is 0.63 (1) Test Ho: p= 0.65 against H:p> 0.65. Use a = 0.05. test statistic z critical z score The final conclusion is OA. We can reject the null hypothesis that p= 0.65 and accept that p > 0.65 OB. There is not sufficient evidence to reject the null hypothesis that p=0.65 (2) Test Ho: p=0.65 against H, :p<0.65. Use a = 0.01 test statistic = critical z score The final conclusion is OA. There is not sufficient evidence to reject the null hypothesis that p=0.65 OB. We can reject the null hypothesis that p= 0.65 and accept that p < 0.65. (3) Test Ho: p=0.6 against He: p0.6. Use a = 0.05 test statistic positive critical score negative critical score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p=0.6. B. We can reject the null hypothesis that p=0.6 and accept that p = 0.6 4

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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(2) A random sample of 120 observations is selected from a binomial population with unknown probability of success p. The computed value of p is 0.63. (1) Test Ho: p=0.65 against H:p> 0.65. Use a = 0.05. test statistic z critical z score The final conclusion is OA. We can reject the null hypothesis that p= 0.65 and accept that p > 0.65 OB. There is not sufficient evidence to reject the null hypothesis that p= 0.65 (2) Test Ho: p= 0.65 against H₁ : p < 0.65. Use a=0.01. test statistic === critical score The final conclusion is OA. There is not sufficient evidence to reject the null hypothesis that p = 0.65 OB. We can reject the null hypothesis that p= 0.65 and accept that p < 0.65. (3) Test Ho: p= 0.6 against Ha: P0.6. Use a = 0.05. test statistic positive critical score negative critical score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p=0.6. OB. We can reject the null hypothesis that p=0.6 and accept that p / 0.6 4
Transcribed Image Text:(2) A random sample of 120 observations is selected from a binomial population with unknown probability of success p. The computed value of p is 0.63. (1) Test Ho: p=0.65 against H:p> 0.65. Use a = 0.05. test statistic z critical z score The final conclusion is OA. We can reject the null hypothesis that p= 0.65 and accept that p > 0.65 OB. There is not sufficient evidence to reject the null hypothesis that p= 0.65 (2) Test Ho: p= 0.65 against H₁ : p < 0.65. Use a=0.01. test statistic === critical score The final conclusion is OA. There is not sufficient evidence to reject the null hypothesis that p = 0.65 OB. We can reject the null hypothesis that p= 0.65 and accept that p < 0.65. (3) Test Ho: p= 0.6 against Ha: P0.6. Use a = 0.05. test statistic positive critical score negative critical score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p=0.6. OB. We can reject the null hypothesis that p=0.6 and accept that p / 0.6 4
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