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·S= 3x5 3x4+6x33x2 - 6x + In Evaluate O x² - 4x 2 O x² - 4x 2 O x2−2x 2 x²-2x-In + In -dx using method of partial fraction +C (x − 1) 1/6(x+2) 16/3 - x + 1 (x-1) 1/6(x+2) 16/3- (x+1) 1/2 (x-1) 1/6(x+2) 16/3 (x+1) 1/2 (x-1) 1/6(x+2) 16/3 (x+1) 1/2 + In - 1 [(x - |+C +C 16/3] + C

·S= 3x5 3x4+6x33x2 - 6x + In Evaluate O x² - 4x 2 O x² - 4x 2 O x2−2x 2 x²-2x-In + In -dx using method of partial fraction +C (x − 1) 1/6(x+2) 16/3 - x + 1 (x-1) 1/6(x+2) 16/3- (x+1) 1/2 (x-1) 1/6(x+2) 16/3 (x+1) 1/2 (x-1) 1/6(x+2) 16/3 (x+1) 1/2 + In - 1 [(x - |+C +C 16/3] + C

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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QUESTION 10 3x5 Evaluate ·S= -dx using method of partial fractions. 3x4+6x33x2 - 6x O x² - 4x (x-1) 1/6(x+2) 16 16/3 + In +C 2 x + 1 O x² - 4x (x-1) 1/6(x+2) 16/3 (x+1) 1/2 2 O x2−2x +In (x-1) 1/6(x+2) 16/3 (x+1) 1/2 2 (x− 1) 1/6(x+2) 16/3- x²-2x-In (x+1) 1/2 + In +C +C + C
Transcribed Image Text:QUESTION 10 3x5 Evaluate ·S= -dx using method of partial fractions. 3x4+6x33x2 - 6x O x² - 4x (x-1) 1/6(x+2) 16 16/3 + In +C 2 x + 1 O x² - 4x (x-1) 1/6(x+2) 16/3 (x+1) 1/2 2 O x2−2x +In (x-1) 1/6(x+2) 16/3 (x+1) 1/2 2 (x− 1) 1/6(x+2) 16/3- x²-2x-In (x+1) 1/2 + In +C +C + C
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