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Run a regression analysis on the following bivariate set of data with y as the response variable. X y 73.8 82.4 67.2 78.2 57.8 74.1 67.7 81.7 66.2 71.7 57.5 82.3 80.1 81.4 58.7 74.9 63 79.9 64 75.2 Find the correlation coefficient and report it accurate to three decimal places. r = 0.417 What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.) √² = 17.4 σ% Based on the data, calculate the regression line (each value to three decimal places) y= 0.227 OX+63.299 08 Predict what value (on average) for the response variable will be obtained from a value of 79.8 as the explanatory variable. Use a significance level of a = 0.05 to assess the strength of the linear correlation. What is the predicted response value? (Report answer accurate to one decimal place.) y= 81.4

Run a regression analysis on the following bivariate set of data with y as the response variable. X y 73.8 82.4 67.2 78.2 57.8 74.1 67.7 81.7 66.2 71.7 57.5 82.3 80.1 81.4 58.7 74.9 63 79.9 64 75.2 Find the correlation coefficient and report it accurate to three decimal places. r = 0.417 What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.) √² = 17.4 σ% Based on the data, calculate the regression line (each value to three decimal places) y= 0.227 OX+63.299 08 Predict what value (on average) for the response variable will be obtained from a value of 79.8 as the explanatory variable. Use a significance level of a = 0.05 to assess the strength of the linear correlation. What is the predicted response value? (Report answer accurate to one decimal place.) y= 81.4

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Run a regression analysis on the following bivariate set of data with y as the response variable. X y 73.8 82.4 67.2 78.2 57.8 74.1 67.7 81.7 66.2 71.7 57.5 82.3 80.1 81.4 58.7 74.9 63 79.9 64 75.2 Find the correlation coefficient and report it accurate to three decimal places. r = 0.417 What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.) √² = 17.4 σ% Based on the data, calculate the regression line (each value to three decimal places) y= 0.227 OX+63.299 08 Predict what value (on average) for the response variable will be obtained from a value of 79.8 as the explanatory variable. Use a significance level of a = 0.05 to assess the strength of the linear correlation. What is the predicted response value? (Report answer accurate to one decimal place.) y= 81.4
Transcribed Image Text:Run a regression analysis on the following bivariate set of data with y as the response variable. X y 73.8 82.4 67.2 78.2 57.8 74.1 67.7 81.7 66.2 71.7 57.5 82.3 80.1 81.4 58.7 74.9 63 79.9 64 75.2 Find the correlation coefficient and report it accurate to three decimal places. r = 0.417 What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.) √² = 17.4 σ% Based on the data, calculate the regression line (each value to three decimal places) y= 0.227 OX+63.299 08 Predict what value (on average) for the response variable will be obtained from a value of 79.8 as the explanatory variable. Use a significance level of a = 0.05 to assess the strength of the linear correlation. What is the predicted response value? (Report answer accurate to one decimal place.) y= 81.4
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