Run 2: Initial grams of NaHCO34.292%3DTheoretical yield (grams) of Na20:Percent yield (Run 2) D 2 NAHCO:(s) >I Na,0(s)2 co.(e)H;O(8)Reaction B4.476Run 1: Initial grams of NaHCO3Theoretical yield (grams) of Na,0:Percent yield (Run 1) =

The given decomposition reaction is: 2NaHCO3(s) ----> Na2O(s) + 2CO2(g) + H2O(l)

Answered: Run 2: Initial grams of NaHCO, 4.292…

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Run 2: Initial grams of NaHCO, 4.292 Theoretical yield (grams) of Na20: Percent yield (Run 2) =

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

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Run 2: Initial grams of NaHCO3
4.292
%3D
Theoretical yield (grams) of Na20:
Percent yield (Run 2) D

2 NAHCO:(s) >
I Na,0(s)
2 co.(e)
H;O(8)
Reaction B
4.476
Run 1: Initial grams of NaHCO3
Theoretical yield (grams) of Na,0:
Percent yield (Run 1) =

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