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Rules of Boolean algebra 1. A+0=A 7. A A A 2. A+1=1 8. A A=0 3. А-0-0 9. A= A 4. A-1 A 10. A+AB= A 5. A+A= A 11. A+AB= A+B 6. A+A=1 12. (A+B)(A+ C) = A+BC HW: 1- Proof the rules (11 & 12) 2- Draw logic diagrams to implement the following Boolean expressions : (1) x. (y+z) (2) (x. y) + (x.z)

Rules of Boolean algebra 1. A+0=A 7. A A A 2. A+1=1 8. A A=0 3. А-0-0 9. A= A 4. A-1 A 10. A+AB= A 5. A+A= A 11. A+AB= A+B 6. A+A=1 12. (A+B)(A+ C) = A+BC HW: 1- Proof the rules (11 & 12) 2- Draw logic diagrams to implement the following Boolean expressions : (1) x. (y+z) (2) (x. y) + (x.z)

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Rules of Boolean algebra 1. A+0= A 7. A A A 2. A+1=1 8. A A 0 %3D 3. A 0=0 9. A A 4. A-1 A 10. A+AB A 5. A+A= A 11. A+AB A+B 6. A+A=1 12. (A+B)(A+ C)= A+ BC HW: 1- Proof the rules (11 & 12) 2- Draw logic diagrams to implement the following Boolean expressions: (1) x. (y+ z) (2) (x. y) + (x.z)
Transcribed Image Text:Rules of Boolean algebra 1. A+0= A 7. A A A 2. A+1=1 8. A A 0 %3D 3. A 0=0 9. A A 4. A-1 A 10. A+AB A 5. A+A= A 11. A+AB A+B 6. A+A=1 12. (A+B)(A+ C)= A+ BC HW: 1- Proof the rules (11 & 12) 2- Draw logic diagrams to implement the following Boolean expressions: (1) x. (y+ z) (2) (x. y) + (x.z)
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