RSSP0 log(- RSSp0+L N - po log N - po - L 2(po + 1) N - po 2((po + L) + 1) N - (po + L) | If we exponentiate both sides, does the inequality sign change? I currently have this after taking exponentials: RSS20 RSS p0+L s 2(Po+L+1) 2(P0+1)} exp N-Po-L N-PO N - po N – po – L Please let me know if this is correct if not, describe intuitively why the inequality must change.
RSSP0 log(- RSSp0+L N - po log N - po - L 2(po + 1) N - po 2((po + L) + 1) N - (po + L) | If we exponentiate both sides, does the inequality sign change? I currently have this after taking exponentials: RSS20 RSS p0+L s 2(Po+L+1) 2(P0+1)} exp N-Po-L N-PO N - po N – po – L Please let me know if this is correct if not, describe intuitively why the inequality must change.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:RSSP0
log(-
RSS20+L
N - po
logl N - po - L
2(po + 1)
N - po
2((po + L) + 1)
N - (Po + L)
If we exponentiate both sides, does the inequality
sign change?
I currently have this after taking exponentials:
S 2(Po+L+1) _2(P0+1) }
RSS20
RSS p0+L
N - po
-exp
N – po – L
Please let me know if this is correct if not, describe
intuitively why the inequality must change.
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