Rs1 R$₂2 Rs2=Zo RLI RL2=Z0 Figure 3 The coupling between the lines will arise in general from the effects of the electric field - capacitive coupling and from the effect of the magnetic field - inductive coupling. It is simplest to deal with these separately. If, as shown, only line 1 is driven
Rs1 R$₂2 Rs2=Zo RLI RL2=Z0 Figure 3 The coupling between the lines will arise in general from the effects of the electric field - capacitive coupling and from the effect of the magnetic field - inductive coupling. It is simplest to deal with these separately. If, as shown, only line 1 is driven
Introductory Circuit Analysis (13th Edition)
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Publisher:Robert L. Boylestad
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Explain paragraph and diagram
![Rs1
R₂₂=Zo
RLI
RL2=Z0
go
Figure 3
The coupling between the lines will arise in general from the effects of the electric
field - capacitive coupling and from the effect of the magnetic field - inductive
coupling. It is simplest to deal with these separately. If, as shown, only line 1 is driven](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd9147e2a-f1a4-4ee2-826b-508a5fd2d6bb%2Fc9f56745-32e8-4942-91fb-018722dac497%2Fjhex7n_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Rs1
R₂₂=Zo
RLI
RL2=Z0
go
Figure 3
The coupling between the lines will arise in general from the effects of the electric
field - capacitive coupling and from the effect of the magnetic field - inductive
coupling. It is simplest to deal with these separately. If, as shown, only line 1 is driven
![then if line 1 is left open-circuit that is RL1 is infinite, then there can be no net current
on line 1 and the coupling is necessarily capacitive. On the other hand if line 1 is
short-circuited then the coupling is inductive.
If the frequency is low enough, then the transmission lines can be regarded as a short
one. A useful guide is the length of the line in question is less than 2/10 at the
frequency f of operation. For the transmission line used in this experiment, fλ = v=
c/Ver where &r is the relative dielectric constant of the medium - a clear plastic
(perspex) in this case.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd9147e2a-f1a4-4ee2-826b-508a5fd2d6bb%2Fc9f56745-32e8-4942-91fb-018722dac497%2F09y0hip_processed.jpeg&w=3840&q=75)
Transcribed Image Text:then if line 1 is left open-circuit that is RL1 is infinite, then there can be no net current
on line 1 and the coupling is necessarily capacitive. On the other hand if line 1 is
short-circuited then the coupling is inductive.
If the frequency is low enough, then the transmission lines can be regarded as a short
one. A useful guide is the length of the line in question is less than 2/10 at the
frequency f of operation. For the transmission line used in this experiment, fλ = v=
c/Ver where &r is the relative dielectric constant of the medium - a clear plastic
(perspex) in this case.
Expert Solution
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Step 1
In the above diagram transmission line is shown, one of the lines is driven by a voltage source while there is no source on the other line.
When the lines will be closer to one another, the electric field of each line will interact with the other and the same will occur for the magnetic field. Thus there are two types of coupling possible, these are:
- Capacitive coupling (due to the electric field of the current carrying lines)
- Inductive coupling (due to the magnetic field of the current carrying lines)
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