rpya fef function.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
Krpya fef function.
![2 This algorithm takes two compatible two dimensional matrix
}
and return their product
1 Space complexity: 0(n^2)
G Possible edge case: the number of columns of multiplicand not consistent with
5
the number of rows of multiplier, will raise exception
7
3
}
3
2
3
1
6
3
}
}
2
8
1
5
6
rrrr Tr
def multiply(multiplicand: list, multiplier; list) -> list;
FT TT TT
:type A: List[List[int]]
:type B: List[List[int]]
:rtype: List[List[int]]
rr TT TT
multiplicand_row, multiplicand_col. = Len(
multiplicand), len(multiplicand[0])
multiplier_row, multiplier_col. = len(multiplier), len(multiplier [0])
if(multiplicand_col [= multiplier_row):
raise Exception(
"Multiplicand matrix not compatible with Multiplier matrix.")
# create a result matrix
result = [[0] * multiplier_col for i in range(multiplicand_row]]
for i in range(multiplicand_row):
for j in range(multiplier_col):
for k in range(len(multiplier)):
result[i][j] += multiplicand[i][k] * multiplier [k][j]
return Facul+](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F975eedeb-cca9-452a-a623-85539861d2ea%2F3d91f59c-c3a4-48a2-b3ce-364e0fdd4535%2Faagx37_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2 This algorithm takes two compatible two dimensional matrix
}
and return their product
1 Space complexity: 0(n^2)
G Possible edge case: the number of columns of multiplicand not consistent with
5
the number of rows of multiplier, will raise exception
7
3
}
3
2
3
1
6
3
}
}
2
8
1
5
6
rrrr Tr
def multiply(multiplicand: list, multiplier; list) -> list;
FT TT TT
:type A: List[List[int]]
:type B: List[List[int]]
:rtype: List[List[int]]
rr TT TT
multiplicand_row, multiplicand_col. = Len(
multiplicand), len(multiplicand[0])
multiplier_row, multiplier_col. = len(multiplier), len(multiplier [0])
if(multiplicand_col [= multiplier_row):
raise Exception(
"Multiplicand matrix not compatible with Multiplier matrix.")
# create a result matrix
result = [[0] * multiplier_col for i in range(multiplicand_row]]
for i in range(multiplicand_row):
for j in range(multiplier_col):
for k in range(len(multiplier)):
result[i][j] += multiplicand[i][k] * multiplier [k][j]
return Facul+
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