Row reducing, we find Therefore, the system has solution 1 2 3 -2 1 2 1 -4 1 2 3 -6 3 36 x1 x2 x3 x4 -3 0 0 1 -2 3 + s 1 0 0 0 1 0 0 +t -2 00 2 0 1 0 1 0 0 1 -1 0 s, tER -3 4 0

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