Row 3, Column 3 X1 X2 X3 S1 S2 S3 z 6 11 1 0 0 250 -5 -14 -8 0 0-460 -1 -1 -3 1 0-510 -10 -50 -30 0 0 1
Row 3, Column 3 X1 X2 X3 S1 S2 S3 z 6 11 1 0 0 250 -5 -14 -8 0 0-460 -1 -1 -3 1 0-510 -10 -50 -30 0 0 1
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Finite Mathematics
Expert Solution
Step 1
Given that
z | |||||||
6 | 11 | 4 | 1 | 0 | 0 | 0 | 250 |
-5 | -14 | -8 | 0 | 1 | 0 | 0 | -460 |
-1 | -1 | -3 | 0 | 0 | 1 | 0 | -510 |
-10 | -50 | -30 | 0 | 0 | 0 | 1 | 0 |
Step:-1
Pivot element is -3 (as given that row 3 and column 3 so crossing element is -3) make it 1 by applying row operation . we get
z | |||||||
6 | 11 | 4 | 1 | 0 | 0 | 0 | 250 |
-5 | -14 | -8 | 0 | 1 | 0 | 0 | -460 |
1* | 0 | 0 | - | 0 | 170 | ||
-10 | -50 | -30 | 0 | 0 | 0 | 1 | 0 |
Step:-2
Here, 1 is pivot element.
Now, make the elements zero, above and below the pivot element.
So applying row operations
we get
z | |||||||
0 | 1 | 0 | 0 | -430 | |||
0 | 0 | 1 | 0 | 900 | |||
1* | 0 | 0 | - | 0 | 170 | ||
0 | -40 | 0 | 0 | 0 | -10 | 1 | 5100 |
This is the required table.
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