Row 3, Column 3 X1 X2 X3 S1 S2 S3 z 6 11 1 0 0 250 -5 -14 -8 0 0-460 -1 -1 -3 1 0-510 -10 -50 -30 0 0 1

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Finite Mathematics
Pivot on the given entry in the tableau.
Row 3, Column 3
X1
X2
X3
S1 S2 S3 z
11
4
1
250
-5 -14 -8
1
0 -460
-1
-1
-3
1
0 -510
- 10 -50 -30
0 1
X1
X2
X3
S1
S2
S3
14
3
900
-10
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Transcribed Image Text:Pivot on the given entry in the tableau. Row 3, Column 3 X1 X2 X3 S1 S2 S3 z 11 4 1 250 -5 -14 -8 1 0 -460 -1 -1 -3 1 0 -510 - 10 -50 -30 0 1 X1 X2 X3 S1 S2 S3 14 3 900 -10 Additional Materials H eBook Submit Answer View Previous Question Question 9 of 20 View N
Expert Solution
Step 1

Given that

x1 x2 x3 s1 s2 s3 z  
6 11 4 1 0 0 0 250
-5 -14 -8 0 1 0 0 -460
-1 -1 -3 0 0 1 0 -510
-10 -50 -30 0 0 0 1 0

Step:-1 

Pivot element is -3 (as given that row 3 and column 3 so crossing element is -3)  make it 1 by applying row operation R3R3 -3. we get

x1 x2 x3 s1 s2 s3 z  
6 11 4 1 0 0 0 250
-5 -14 -8 0 1 0 0 -460
13 13 1* 0 0 -13 0 170
-10 -50 -30 0 0 0 1 0

Step:-2

Here, 1 is pivot element.

Now, make the elements zero, above and below the pivot element.

So applying row operations 

R1R1 -4R3,  R2R2+8R3,  R4R4 +30R3

we get

x1 x2 x3 s1 s2 s3 z  
143 293 0 1 0 43 0 -430
-73 -343 0 0 1 -83 0 900
13 13 1* 0 0 -13 0 170
0 -40 0 0 0 -10 1 5100

This is the required table.

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