Rotational Kinetic A 30.5 kg block (m1) is on a horizontal surface, connected to a 5.10 kg block (m2) by a massless string as shown in the Figure below. The frictionless pulley has a radius R = 0.054 m and a moment of inertia I=0.090 kgm2. A force F = 200.9 N acts on m1 at an angle θ = 29.5°. There is no friction between m1 and the surface. What is the upward acceleration of m2?
Rotational Kinetic A 30.5 kg block (m1) is on a horizontal surface, connected to a 5.10 kg block (m2) by a massless string as shown in the Figure below. The frictionless pulley has a radius R = 0.054 m and a moment of inertia I=0.090 kgm2. A force F = 200.9 N acts on m1 at an angle θ = 29.5°. There is no friction between m1 and the surface. What is the upward acceleration of m2?
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Rotational Kinetic
A 30.5 kg block (m1) is on a horizontal surface, connected to a 5.10 kg block (m2) by a massless string as shown in the Figure below. The frictionless pulley has a radius R = 0.054 m and a moment of inertia I=0.090 kgm2. |
A force F = 200.9 N acts on m1 at an angle θ = 29.5°. There is no friction between m1 and the surface. What is the upward acceleration of m2?
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Step 1: Introduction of given data
VIEWStep 2: here we draw the free body diagram for both blocks and pulley
VIEWStep 3: here we use we apply the Newton's second law of motion for both blocks and use formula of torque.
VIEWStep 4: here we put the value of T1 and T2 in eq(3) and find the acceleration
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