can you answer the question PROBLEM 3:The configuration of a furnace can beapproximated as an equilateral triangular ductwhich is sufficiently long tht the ends arenegligible. The hot wall is maintained at T1-900Kand has an emissivity &1=0.8. The wall ismaintained at T2=400 K and has an emissivityE2=0.8. The third wall is reradiating zone for whichQ3=0. Calculate the net heat flux leaving the how900 KT2 = 400 K€; = 0.8€2 = 0.86060wall.Reradiating

Data given - T1 = 900 K e1 = 0.8 T2 = 400 K e2 = 0.8 Q= ?

ROBLEM 3: The configuration of a furnace can be approximated as an equilateral triangular duct which is sufficiently long tht the ends are negligible. The hot wall is maintained at T=900 K and has an emissivity &=0.8. The wall is maintained at T2=400 K and has an emissivity E2=0.8. The third wall is reradiating zone for which Q3=0. Calculate the net heat flux leaving the how = 900 K * 400 K T2 €2 = 0.8 = 0.8 wall. 60° 60° Reradiating

ROBLEM 3: The configuration of a furnace can be approximated as an equilateral triangular duct which is sufficiently long tht the ends are negligible. The hot wall is maintained at T=900 K and has an emissivity &=0.8. The wall is maintained at T2=400 K and has an emissivity E2=0.8. The third wall is reradiating zone for which Q3=0. Calculate the net heat flux leaving the how = 900 K * 400 K T2 €2 = 0.8 = 0.8 wall. 60° 60° Reradiating

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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