Problem #2: A number is divisible by 11 if the difference of the sum of its digits at odd places and the sum ofts digits at even places is either 0 or divisible by 11.For example, for 2547039:(Sum of digits at odd places) - (Sum of digits at even places) = (9 + 0 +4 + 2) - (3+7+5)=D0So 2547039 is divisible by Il,But for 13165648:(Sum of digits at odd places)- (Sum of digits at even places) = (8+6+6 +3) - (4+5 +1+1)= 1212 is not divisible by 11 so 13165648 is also not divisible by 11.Sample run:Total is: 1213165648 is not divisible by 11.

Since the input number may be very large, so we use the string type variable (num) to store it. Then…

roblem #2: A number is divisible by 11 if the difference of the sum of its digits at odd places and the sum of s digits at even places is either 0 or divisible by 11. For example, for 2547039: (Sum of digits at odd places) - (Sum of digits at even places) = (9+0 + 4 + 2) - (3+7+5)%3D0 So 2547039 is divisible byll. But for 13165648: (Sum of digits at odd places) - (Sum of digits at even places) - (8+ 6 + 6 + 3) - (4 +5 +1 + 1)= 12 12 is not divisible by 11 so 13165648 is also not divisible by 11. Sample run: Give your number: 13165648 Total is: 12 13165648 is not divisible by 11.

roblem #2: A number is divisible by 11 if the difference of the sum of its digits at odd places and the sum of s digits at even places is either 0 or divisible by 11. For example, for 2547039: (Sum of digits at odd places) - (Sum of digits at even places) = (9+0 + 4 + 2) - (3+7+5)%3D0 So 2547039 is divisible byll. But for 13165648: (Sum of digits at odd places) - (Sum of digits at even places) - (8+ 6 + 6 + 3) - (4 +5 +1 + 1)= 12 12 is not divisible by 11 so 13165648 is also not divisible by 11. Sample run: Give your number: 13165648 Total is: 12 13165648 is not divisible by 11.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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