robability. An airline knows from experience that the distribution of the number of suitcases that get lost each week on a certain route is approximately normal with µ = 15.5 and o = 3.6. What is the probability that during a given week the airline will lose between 10 and 20 suitcases? 0.1056 0.4040 0.3944 0.8314

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### Find the Indicated Probability

An airline knows from experience that the distribution of the number of suitcases that get lost each week on a certain route is approximately normal with mean (μ) = 15.5 and standard deviation (σ) = 3.6. What is the probability that during a given week the airline will lose between 10 and 20 suitcases?

#### Answer Choices:
- ○ 0.1056
- ○ 0.4040
- ○ 0.3944
- ○ 0.8314

#### Explanation:
The problem requires determining the probability that a normally distributed random variable falls between 10 and 20, given a mean (μ) and standard deviation (σ). This can be solved using the standard normal distribution (Z-distribution) and Z-scores.

No graphs or diagrams are presented in this image. However, a normal distribution curve can be imagined, centered at the mean (μ) = 15.5, with areas under the curve corresponding to the given probabilities.

### Key Points:
1. **Normal Distribution**: The data follows a bell-shaped, symmetric curve centered around the mean.
2. **Z-score Calculation**: Conversion of the values (10 and 20 in this case) to Z-scores.
3. **Probability Determination**: Use Z-tables or statistical software to find the area under the standard normal curve corresponding to the Z-scores, which represent the probabilities.
Transcribed Image Text:### Find the Indicated Probability An airline knows from experience that the distribution of the number of suitcases that get lost each week on a certain route is approximately normal with mean (μ) = 15.5 and standard deviation (σ) = 3.6. What is the probability that during a given week the airline will lose between 10 and 20 suitcases? #### Answer Choices: - ○ 0.1056 - ○ 0.4040 - ○ 0.3944 - ○ 0.8314 #### Explanation: The problem requires determining the probability that a normally distributed random variable falls between 10 and 20, given a mean (μ) and standard deviation (σ). This can be solved using the standard normal distribution (Z-distribution) and Z-scores. No graphs or diagrams are presented in this image. However, a normal distribution curve can be imagined, centered at the mean (μ) = 15.5, with areas under the curve corresponding to the given probabilities. ### Key Points: 1. **Normal Distribution**: The data follows a bell-shaped, symmetric curve centered around the mean. 2. **Z-score Calculation**: Conversion of the values (10 and 20 in this case) to Z-scores. 3. **Probability Determination**: Use Z-tables or statistical software to find the area under the standard normal curve corresponding to the Z-scores, which represent the probabilities.
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