rnal pin) pent 3' p lok.ft B5 с F I al Sek F 2k/ft 44²+4²-9 8 ft 6ft, 6ft +4 + E # It K 3.3 ttt off 6ft
rnal pin) pent 3' p lok.ft B5 с F I al Sek F 2k/ft 44²+4²-9 8 ft 6ft, 6ft +4 + E # It K 3.3 ttt off 6ft
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
Determined the reactions at the supports

Transcribed Image Text:The diagram appears to be a structural analysis problem, showing a beam with various forces acting on it. Here is a detailed description:
### Beam and Forces:
1. **Beam Segment:**
- The beam is horizontal and is sectioned into different parts with specified lengths.
2. **Support and Locations:**
- Point A: This is a fixed support on the left end of the beam.
- Point B: A location on the beam with a moment of 10 Kips-foot (Kip-ft).
- Points C and D: Locations on the beam where additional forces and loads are applied.
3. **Forces and Loads:**
- A distributed load of 2 Kips per foot (K/ft) is acting between points C and D, spanning a distance of 4 feet.
- An additional point load is indicated further down the beam.
4. **Distances:**
- The beam segments are labeled with distances of 6 ft, 6 ft, 8 ft, and two subsequent segments of 3 ft each.
### Diagonal Support:
- The right side of the diagram features a diagonal support spanning vertically and horizontally:
- Point E: Horizontal distance of 12 ft where a tension force K is pulling to the right.
- Point F: Vertical distance from E to the support, totaling 12 ft (6 ft + 6 ft).
### Calculations:
- Below the diagram, there’s a calculation noted as “-15,” possibly referring to a resultant force calculation or reaction.
This structural setup likely represents a problem where the goal is to determine the reaction forces at supports or to find bending moments along the beam.
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Given data,
fig is given
FIND
reactions at the supports
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