rify that 2, is an eigenvalue of A and that x, is a corresponding eigenvector. а13 -11, х, 3 (1, 2, -1) 6, 12 = -3, x, = (-2, 1 0) d3 = -3, x3 = (3, 0, 1) -4 -2 3 A = -2 -7 1 2 -6 -4 -2 3 1 -2 -7 6 2 = -11 2 = 1,x1 %3D 1 2 -6 -1 - -4 -2 3 -2 -2 2 = -2 -7 6 1 = -3 = 12x2 2 -6 JL -- E -4 -2 3 = -2 -7 -3 = 13×3 1 2 -6 11

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