**Tow Truck and Lifting Force Analysis**In this illustration, a tow truck is shown with a cable applying a tensional force of 1000 N. The cable is at a 60-degree angle relative to the horizontal. **Problem Statement:**Consider the tow truck in the image. If the tensional force in the cable is 1000 N and the cable makes a 60-degree angle with the horizontal, what is the vertical component of the force that lifts the car off the ground?**Diagram Explanation:**- The tow truck is depicted with a blue rectangular body and wheels.- A cable extends from the truck to a red object (representing a car), forming a 60-degree angle with the horizontal.- An arrow along the cable direction indicates the force, labeled as F = 1000 N.To find the vertical component of the force, use the formula:\[ F_{\text{vertical}} = F \cdot \sin(\theta) \]where \( \theta = 60^\circ \) and \( F = 1000 \, \text{N} \).

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Description: **Tow Truck and Lifting Force Analysis**In this illustration, a tow truck is shown with a cable applying a tensional force of 1000 N. The cable is at a 60-degree angle relative to the horizontal. **Problem Statement:**Consider the tow truck in the i

Given data: Tension force (F) = 1000 N Angle (θ) = 60°,with the horizontal Required: The vertical…

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RF-1000 N 60° Consider the tow truck at the right. If the tensional force in the cable is 1000 N and if the cable makes a 60-degree angle with the horizontal, then what is the vertical component of force that lifts the car off the ground?

RF-1000 N 60° Consider the tow truck at the right. If the tensional force in the cable is 1000 N and if the cable makes a 60-degree angle with the horizontal, then what is the vertical component of force that lifts the car off the ground?

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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**Tow Truck and Lifting Force Analysis**

In this illustration, a tow truck is shown with a cable applying a tensional force of 1000 N. The cable is at a 60-degree angle relative to the horizontal.

**Problem Statement:**
Consider the tow truck in the image. If the tensional force in the cable is 1000 N and the cable makes a 60-degree angle with the horizontal, what is the vertical component of the force that lifts the car off the ground?

**Diagram Explanation:**
- The tow truck is depicted with a blue rectangular body and wheels.
- A cable extends from the truck to a red object (representing a car), forming a 60-degree angle with the horizontal.
- An arrow along the cable direction indicates the force, labeled as F = 1000 N.

To find the vertical component of the force, use the formula:
\[ F_{\text{vertical}} = F \cdot \sin(\theta) \]
where \( \theta = 60^\circ \) and \( F = 1000 \, \text{N} \).

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