RSubmit AnswerThe rate of effusion of CH4 gas through a porous barrier is observed to be 9.68 x 10-4 mol/h.Under the same conditions, the rate of effusion of CO2 gas would bemol/h.%5JJTF5Retry Entire Grouptv N6[Review Topics][References]Use the References to access important values if needed for this question.cator=assignment-takeF6行道A O B6 more group attempts remainingMacBook Air&7F78FB(9F9P 人口.Previous S6Submit AnswerH[Review Topics][References]Use the References to access important values if needed for this question.A sample of Xe gas is observed to effuse through a porous barrier in 3.94 minutes. Under the same conditions, the same numberof moles of an unknown gas requires 2.13 minutes to effuse through the same barrier.The molar mass of the unknown gas isg/mol.F6MacBook Air&7URetry Entire GroupAKF7* 00Activity.do?locatorssignment-take8-FB6 more group attempts remaining(9OChapter 5 Homework (D XFO0PF10J+ 11OWLv2 | Online teaching XPreviousSNextSave and Exit☎98OWLv2 | Assignments |Q

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Answered: [Review Topics] [References] Use the…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The rate of effusion of CH4 gas through a porous barrier is observed to be 9.68 x 10-4 mol/h.
Under the same conditions, the rate of effusion of CO2 gas would be
mol/h.
%
5
JJ
T
F5
Retry Entire Group
tv N
6
[Review Topics]
[References]
Use the References to access important values if needed for this question.
cator=assignment-take
F6
行道
A O B
6 more group attempts remaining
MacBook Air
&
7
F7
8
FB
(
9
F9
P 人口
.
Previous

Expert Solution

Step 1: Interpretation of datas :

$1. G i v e n space comma r a t e space o f space e f f u s i o n space o f space C H subscript 4 equals 9.68 cross times 10 to the power of negative 4 end exponent fraction numerator m o l over denominator h end fraction O b j e c t i v e space colon space C a l c u l a t space r a t e space o f space e f f u s i o n space o f space C O subscript 2 2. G i v e comma X e space e f f u s e s space i n space 3.94 space m i n. O b j e c t i v e space colon space C a l c u l a t e space m o l a r space m a s s space o f space u n k n o w n space g a s space.$

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