Review the following chemical reaction and data table provided. HCI (aq) + NaOH (aq) --> NaCI (s) + H2O (I) 36.5 g 40.0 g Mass of HCI Mass of NaOH Mass of NaCI 58.5 g Mass of H20 ?? What mass of water is expected to be produced in the reaction above?

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A.18.0 g because mass is created for the final product. 

 

B. 18.0 because the mass of the products must equal the mass of the reactants

 

C. 76.5 g because mass cannot be created or destroyed

 

D. 76.5 g because the mass of the final product must equal the reactants.

**Chemical Reaction and Data Analysis**

**Reaction:**  
\[ \text{HCl (aq) + NaOH (aq) } \rightarrow \text{ NaCl (s) + H}_2\text{O (l)} \]

**Data Table:**

| Substance  | Mass         |
|------------|--------------|
| Mass of HCl| 36.5 g       |
| Mass of NaOH| 40.0 g     |
| Mass of NaCl| 58.5 g     |
| Mass of H₂O | ??          |

**Problem Question:**  
What mass of water is expected to be produced in the reaction above?

**Explanation of Table:**

The table lists the masses of hydrochloric acid (HCl), sodium hydroxide (NaOH), sodium chloride (NaCl), and the unknown mass of water (H₂O) that is produced in the reaction. Based on the law of conservation of mass, the total mass of reactants (HCl and NaOH) must equal the total mass of products (NaCl and H₂O). 

**Calculation:**

- Total mass of reactants = Mass of HCl + Mass of NaOH = 36.5 g + 40.0 g = 76.5 g
- Total mass of products = Mass of NaCl + Mass of H₂O = 58.5 g + Mass of H₂O

To find the mass of H₂O, set the total mass of reactants equal to the total mass of products:

\[ 76.5 \text{ g} = 58.5 \text{ g} + \text{Mass of H}_2\text{O} \]

\[ \text{Mass of H}_2\text{O} = 76.5 \text{ g} - 58.5 \text{ g} = 18.0 \text{ g} \]

Therefore, the expected mass of water produced in the reaction is 18.0 grams.
Transcribed Image Text:**Chemical Reaction and Data Analysis** **Reaction:** \[ \text{HCl (aq) + NaOH (aq) } \rightarrow \text{ NaCl (s) + H}_2\text{O (l)} \] **Data Table:** | Substance | Mass | |------------|--------------| | Mass of HCl| 36.5 g | | Mass of NaOH| 40.0 g | | Mass of NaCl| 58.5 g | | Mass of H₂O | ?? | **Problem Question:** What mass of water is expected to be produced in the reaction above? **Explanation of Table:** The table lists the masses of hydrochloric acid (HCl), sodium hydroxide (NaOH), sodium chloride (NaCl), and the unknown mass of water (H₂O) that is produced in the reaction. Based on the law of conservation of mass, the total mass of reactants (HCl and NaOH) must equal the total mass of products (NaCl and H₂O). **Calculation:** - Total mass of reactants = Mass of HCl + Mass of NaOH = 36.5 g + 40.0 g = 76.5 g - Total mass of products = Mass of NaCl + Mass of H₂O = 58.5 g + Mass of H₂O To find the mass of H₂O, set the total mass of reactants equal to the total mass of products: \[ 76.5 \text{ g} = 58.5 \text{ g} + \text{Mass of H}_2\text{O} \] \[ \text{Mass of H}_2\text{O} = 76.5 \text{ g} - 58.5 \text{ g} = 18.0 \text{ g} \] Therefore, the expected mass of water produced in the reaction is 18.0 grams.
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