Review | Constants l chlorine gas has a volume of 0.30 L at Then substitute V = 0.30 L. T= 273 K. and V=1.2 Linto the above equatie your calculation such that the units L cancet leaving you with the unit of temperature convert the temperature in kelvins (K) to degrees Celsius ("C) These calculations ca summarized as follows 273 K and 1 atm pressure. You may want to reference (Pages 230-231) Section 8.6 while completing this problem. | (1.2 K)(273 K)' (0.30 E) T3 273.15 = 819 K %3D Part B What temperature in "C would be required to decrease the volume to 0 18 L? Express your answer using two significant figures. Templates Symbo undo edo reset keyboard shortcuts help T= Submit 8euat Ananr
Review | Constants l chlorine gas has a volume of 0.30 L at Then substitute V = 0.30 L. T= 273 K. and V=1.2 Linto the above equatie your calculation such that the units L cancet leaving you with the unit of temperature convert the temperature in kelvins (K) to degrees Celsius ("C) These calculations ca summarized as follows 273 K and 1 atm pressure. You may want to reference (Pages 230-231) Section 8.6 while completing this problem. | (1.2 K)(273 K)' (0.30 E) T3 273.15 = 819 K %3D Part B What temperature in "C would be required to decrease the volume to 0 18 L? Express your answer using two significant figures. Templates Symbo undo edo reset keyboard shortcuts help T= Submit 8euat Ananr
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Review | Constants
Then substitute V = 0.30 L T = 273 K. and V = 1.2 Linto the above equatio
your calculation such that the units L cancel, leaving you with the unit of temperature
convert the temperature in kelvins (K) to degrees Celsius CC) These calculations ca
A sample of chlorine gas has a volume of 0.30 L at
273 K and 1 atm pressure.
You may want to
reference (Pages 230 - 231) Section 8.6 while
completing this problem.
summarized as follows
(1.2 E)(273 K) |
(0.30 E)
T2 =
273.15 = 819 K
!3!
A.
Part B
What temperature (in "C) would be required to decrease the volume to 0.18 L?
Express your answer using two significant figures.
Templates Symbols undo do reset keyboard shortcuts help
T=
Submit
BenustAnaer](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F118dc5f9-8f0c-4d22-9a05-fca34d762e0b%2F3df56c85-da69-4f8e-8cae-b5bff0b7d58d%2F54x382o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Review | Constants
Then substitute V = 0.30 L T = 273 K. and V = 1.2 Linto the above equatio
your calculation such that the units L cancel, leaving you with the unit of temperature
convert the temperature in kelvins (K) to degrees Celsius CC) These calculations ca
A sample of chlorine gas has a volume of 0.30 L at
273 K and 1 atm pressure.
You may want to
reference (Pages 230 - 231) Section 8.6 while
completing this problem.
summarized as follows
(1.2 E)(273 K) |
(0.30 E)
T2 =
273.15 = 819 K
!3!
A.
Part B
What temperature (in "C) would be required to decrease the volume to 0.18 L?
Express your answer using two significant figures.
Templates Symbols undo do reset keyboard shortcuts help
T=
Submit
BenustAnaer
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