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Review | Constants l chlorine gas has a volume of 0.30 L at Then substitute V = 0.30 L. T= 273 K. and V=1.2 Linto the above equatie your calculation such that the units L cancet leaving you with the unit of temperature convert the temperature in kelvins (K) to degrees Celsius ("C) These calculations ca summarized as follows 273 K and 1 atm pressure. You may want to reference (Pages 230-231) Section 8.6 while completing this problem. | (1.2 K)(273 K)' (0.30 E) T3 273.15 = 819 K %3D Part B What temperature in "C would be required to decrease the volume to 0 18 L? Express your answer using two significant figures. Templates Symbo undo edo reset keyboard shortcuts help T= Submit 8euat Ananr

Review | Constants l chlorine gas has a volume of 0.30 L at Then substitute V = 0.30 L. T= 273 K. and V=1.2 Linto the above equatie your calculation such that the units L cancet leaving you with the unit of temperature convert the temperature in kelvins (K) to degrees Celsius ("C) These calculations ca summarized as follows 273 K and 1 atm pressure. You may want to reference (Pages 230-231) Section 8.6 while completing this problem. | (1.2 K)(273 K)' (0.30 E) T3 273.15 = 819 K %3D Part B What temperature in "C would be required to decrease the volume to 0 18 L? Express your answer using two significant figures. Templates Symbo undo edo reset keyboard shortcuts help T= Submit 8euat Ananr

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Review | Constants Then substitute V = 0.30 L T = 273 K. and V = 1.2 Linto the above equatio your calculation such that the units L cancel, leaving you with the unit of temperature convert the temperature in kelvins (K) to degrees Celsius CC) These calculations ca A sample of chlorine gas has a volume of 0.30 L at 273 K and 1 atm pressure. You may want to reference (Pages 230 - 231) Section 8.6 while completing this problem. summarized as follows (1.2 E)(273 K) | (0.30 E) T2 = 273.15 = 819 K !3! A. Part B What temperature (in "C) would be required to decrease the volume to 0.18 L? Express your answer using two significant figures. Templates Symbols undo do reset keyboard shortcuts help T= Submit BenustAnaer
Transcribed Image Text:Review | Constants Then substitute V = 0.30 L T = 273 K. and V = 1.2 Linto the above equatio your calculation such that the units L cancel, leaving you with the unit of temperature convert the temperature in kelvins (K) to degrees Celsius CC) These calculations ca A sample of chlorine gas has a volume of 0.30 L at 273 K and 1 atm pressure. You may want to reference (Pages 230 - 231) Section 8.6 while completing this problem. summarized as follows (1.2 E)(273 K) | (0.30 E) T2 = 273.15 = 819 K !3! A. Part B What temperature (in "C) would be required to decrease the volume to 0.18 L? Express your answer using two significant figures. Templates Symbols undo do reset keyboard shortcuts help T= Submit BenustAnaer
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