Review It's nighttime, and you've dropped your goggles into a 2.8-m- deep swimming pool. If you hold a laser pointer 1.0 m above the edge of the pool, you can illuminate the goggles if the laser beam enters the water 2.2 m from the edge. Part A How far are the goggles from the edge of the pool? Express your answer to two significant figures and include the appropriate units.
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- 58. A magnifying glass is a converging lens, which could be used to make a real image of an object. A small lightbulb is placed 25.0 cm in front of a convex lens with a focal length of 10.0 cm. a. G Draw a ray-tracing diagram to find the position of the image formed by the lens. b. N Calculate the location and magnification of the image to confirm the accuracy of your drawing.53. N An object is placed 10.0 cm in front of a diverging lens of focal length -6.00 cm. Determine the image magnification and the image distance. 54 An obiect is placed 14.0 cm in front of o diuorgi long withA person's prescription for her new bifocal glasses calls for a refractive power of -0.500 diopters in the distance-vision part, and a power of 1.65 diopters in the close-vision part. Part A What are the near and far points of this person's uncorrected vision? Assume the glasses are 2.00 cm from the person's eyes, and that the person's near-point distance is 25.0 cm when wearing the glasses. Enter your answers numerically separated by a comma. dfar point, dnear point = 15. ΑΣΦ ? m
- The vision of a nearsighted colleague has a near point of 50 cm and a far point of 100 cm. Part A In order to see distant objects correctly, what power lens does she/he need in order to correct her/his vision? -2.0 D -1.0 D 1.0 D 2.0 D Submit Request AnswerHelp with problem BA nearsighted woman has a far point of 280 cmcm . Part A What kind of lens, converging or diverging, should be prescribed for her to see distant objects more clearly? converging diverging she doesn't need lens not enough information to estimate Part B What refractive power should the lens have? Express your answer in diopters.
- Part A A 1.2-cm-tall object is 78 cm in front of a diverging lens that has a -39 cm focal length. Calculate the image position. Express your answer to two significant figures and include the appropriate units. HÀ ? s' = Value Units Submit Request Answer Part B Calculate the image height. Express your answer to two significant figures and include the appropriate units. HA ? h' = Value Units Submit Request AnswerPart A A converging lens with a focal length of 60 cm and a diverging lens with a focal length of -50 cm are 290 cm apart. A 3.5-cm-tall object is 80 cm in front of the converging lens. Calculate the image position relative to the diverging lens. Express your answer to two significant figures and include the appropriate units. Enter a positive value if the image is on the other side from the lens and a negative value if the image is on the same side. HẢ ? s'2 Value Units %D Submit Request Answer Part B Calculate the image height. Express your answer to two significant figures and include the appropriate units. HA h' = Value Units %3D Submit Request AnswerA-6.10-D lens is held 14.5 cm from an ant 1.00 mm high. Part A What is the position of the image? on the opposite side of the lens relative to the object on the same side of the lens with the object no image is formed Previous Answers ✓ Correct Part B Find the image distance. Follow the sign conventions. Express your answer to three significant figures and include the appropriate units. di = -7.69x10-² m Previous Answers ✓ Correct P Pearson Copyright © 2022 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions | Contact Us | MacBook Air
- Luis is nearsighted. To correct his vision, he wears a diverging eyeglass lens with a focal length of -0.50 m. When wearing glasses, Luis looks not at an object but at the virtual image of the object because that is the point from which diverging rays enter his eye. Suppose Luis, while wearing his glasses, looks at a vertical 14-cm-tall pencil that is 2.0 m in front of his glasses.Part A A stamp collector uses a converging lens with a focal length 50.0 mm to view a stamp 70.0 mm in front of the lens. Where is the image located? 175.0 mm You are correct. Your receipt no. is 168-5755 ? Previous Tries Part B Is the image real or virtual? Upright or inverted? Larger or smaller than the object? In front or behind the lens? V Real (R) or Virtual(V) I✓ Upright(U) or Inverted(I) L✓ Larger (L) or Smaller(S) F✓ In Front (F) or Behind (B) the lens An image is in front of the lens if it is on the same side as the object. Submit Answer Incorrect. Tries 3/6 Previous Tries