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Review I C- Part A A container holds 9 g of neon at a pressure of 5.0 atm and a temperature of 15 °C. How much work must be done on the gas to reduce the volume by 50% in a constant-pressure process? Express your answer with the appropriate units. Wp = Value Units Submit Request Answer Part B How much work must be done on the gas to reduce the volume by 50% in a constant-temperature process? Express your answer with the appropriate units. HA

Review I C- Part A A container holds 9 g of neon at a pressure of 5.0 atm and a temperature of 15 °C. How much work must be done on the gas to reduce the volume by 50% in a constant-pressure process? Express your answer with the appropriate units. Wp = Value Units Submit Request Answer Part B How much work must be done on the gas to reduce the volume by 50% in a constant-temperature process? Express your answer with the appropriate units. HA

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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I Review IC ▼ Part A A container holds 9 g of neon at a pressure of 5.0 atm and a temperature of 15 °C. How much work must be done on the gas to reduce the volume by 50% in a constant-pressure process? Express your answer with the appropriate units. W, = Value Units Submit Request Answer Part B How much work must be done on the gas to reduce the volume by 50% in a constant-temperature process? Express your answer with the appropriate units. HA
Transcribed Image Text:I Review IC ▼ Part A A container holds 9 g of neon at a pressure of 5.0 atm and a temperature of 15 °C. How much work must be done on the gas to reduce the volume by 50% in a constant-pressure process? Express your answer with the appropriate units. W, = Value Units Submit Request Answer Part B How much work must be done on the gas to reduce the volume by 50% in a constant-temperature process? Express your answer with the appropriate units. HA
Expert Solution
Step 1

Here initial volume ,Vin = nRT/P where n is no of moles of neon = 9/20= 0.45moles .

and R is gas constant= 0.082 L.atm.K-1.mol-1

and T is Temperature =15°C = 273+15=288 K .

So V = (0.45×0.082×288)÷5= 2.12 L .

Also final volume is 50% of it so Vfin= 2.12/2= 1.06 L .

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