Review I C- Part A A container holds 9 g of neon at a pressure of 5.0 atm and a temperature of 15 °C. How much work must be done on the gas to reduce the volume by 50% in a constant-pressure process? Express your answer with the appropriate units. Wp = Value Units Submit Request Answer Part B How much work must be done on the gas to reduce the volume by 50% in a constant-temperature process? Express your answer with the appropriate units. HA

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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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I Review IC
▼
Part A
A container holds 9 g of neon at a pressure of
5.0 atm and a temperature of 15 °C.
How much work must be done on the gas to reduce the volume by 50% in a constant-pressure process?
Express your answer with the appropriate units.
W, = Value
Units
Submit
Request Answer
Part B
How much work must be done on the gas to reduce the volume by 50% in a constant-temperature process?
Express your answer with the appropriate units.
HA
Transcribed Image Text:I Review IC ▼ Part A A container holds 9 g of neon at a pressure of 5.0 atm and a temperature of 15 °C. How much work must be done on the gas to reduce the volume by 50% in a constant-pressure process? Express your answer with the appropriate units. W, = Value Units Submit Request Answer Part B How much work must be done on the gas to reduce the volume by 50% in a constant-temperature process? Express your answer with the appropriate units. HA
Expert Solution
Step 1

Here initial volume ,Vin = nRT/P where n is no of moles of neon = 9/20= 0.45moles .

and R is gas constant= 0.082 L.atm.K-1.mol-1

and T is Temperature =15°C = 273+15=288 K .

So V = (0.45×0.082×288)÷5= 2.12 L .

Also final volume is 50% of it so Vfin= 2.12/2= 1.06 L .

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