Review Hooke's law describes an ideal spring, Many real springs are better described by the restoring force (Fsp),--kAs- q(As), where q is a constant. Consider a spring with k = 350 N/m and 9=750 N/m Part A How much work must you do to compress this spring 15 cm? Note that, by Newton's third law, the work you do on the spring is the negative of the work done by the spriıng Express your answer with the appropriate units. • View Available Hint(s) W = 4.0 J Submit Previous Answers v Correct Part B By what percent has the cubic term increased the work over what would be needed to compress an ideal spring? Express your answer as a percentage. > View Available Hint(s) AW = 2.35 Submit

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Hooke's law describes an ideal spring. Many real springs are better described by the restoring force (Fsp)s = -k∆s - q(∆s)^3, where q is a constant. Consider a spring with k = 350 N/m and q = 750 N/m^3. By what percent has the cubic term increased the work over what would be needed to compress an ideal spring? (Note: I already answered part A and got 4.0 J)
**Hooke's Law and Spring Compression**

**Overview:**
Hooke's law describes the behavior of an ideal spring, relating the force needed to compress or extend a spring to the distance it is stretched. However, some real springs exhibit additional restoring forces, described by the equation:

\[ F_{SP} = -kΔs - q(Δs)^3 \]

where \( k \) is the spring constant and \( q \) is a parameter accounting for nonlinearity.

Given values:
- \( k = 350 \, \text{N/m} \)
- \( q = 750 \, \text{N/m}^3 \)

**Part A: Calculating Work for Spring Compression**

*Question:*
How much work must you do to compress this spring by 15 cm (0.15 m)? According to Newton's third law, the work you do on the spring is the negative of the work done by the spring.

*Solution:*
Express your answer with the appropriate units:

The calculated work \( W \) to compress the spring is given as 4.0 J (joules).

**Part B: Effect of Nonlinearity on Spring Work**

*Question:*
By what percentage has the cubic term increased the work over what would be needed to compress an ideal spring?

*Solution:*
Express your answer as a percentage:

The percent increase in work due to the cubic term is calculated as 2.35%.

This illustrates how the cubic term affects the energy needed compared to an ideal spring model.

**Conclusion:**
Understanding these concepts allows students to appreciate deviations from ideal behaviors in real-world applications.
Transcribed Image Text:**Hooke's Law and Spring Compression** **Overview:** Hooke's law describes the behavior of an ideal spring, relating the force needed to compress or extend a spring to the distance it is stretched. However, some real springs exhibit additional restoring forces, described by the equation: \[ F_{SP} = -kΔs - q(Δs)^3 \] where \( k \) is the spring constant and \( q \) is a parameter accounting for nonlinearity. Given values: - \( k = 350 \, \text{N/m} \) - \( q = 750 \, \text{N/m}^3 \) **Part A: Calculating Work for Spring Compression** *Question:* How much work must you do to compress this spring by 15 cm (0.15 m)? According to Newton's third law, the work you do on the spring is the negative of the work done by the spring. *Solution:* Express your answer with the appropriate units: The calculated work \( W \) to compress the spring is given as 4.0 J (joules). **Part B: Effect of Nonlinearity on Spring Work** *Question:* By what percentage has the cubic term increased the work over what would be needed to compress an ideal spring? *Solution:* Express your answer as a percentage: The percent increase in work due to the cubic term is calculated as 2.35%. This illustrates how the cubic term affects the energy needed compared to an ideal spring model. **Conclusion:** Understanding these concepts allows students to appreciate deviations from ideal behaviors in real-world applications.
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