Review Conceptual Example 7 as background for this problem. A positive charge +91 is located to the left of a negative charge -92. On a line passing though the two charges, there are two places where the total potential is zero. The first place is between the charges and is 2.61 cm to the left of the negative charge. The second place is 6.21 cm to the right of the negative charge. (a) What is the distance between the charges? (b) Find 9₁/92, the ratio of the magnitudes of the charges. (a) Number i (b) Number i +9₁ Units Units V=OV cm -92 1 V=OV

Review Conceptual Example 7 as background for this problem. A positive charge +91 is located to the left of a negative charge -92. On a line passing though the two charges, there are two places where the total potential is zero. The first place is between the charges and is 2.61 cm to the left of the negative charge. The second place is 6.21 cm to the right of the negative charge. (a) What is the distance between the charges? (b) Find 9₁/92, the ratio of the magnitudes of the charges. (a) Number i (b) Number i +9₁ Units Units V=OV cm -92 1 V=OV

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter25: Electric Potential

Section: Chapter Questions

Problem 25.20P: At a certain distance from a charged particle, the magnitude of the electric field is 500 V/m and...

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An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.

Question

Review Conceptual Example 7 as background for this problem. A positive charge +9₁ is located to the left of a negative charge -92. On a
line passing though the two charges, there are two places where the total potential is zero. The first place is between the charges and is
2.61 cm to the left of the negative charge. The second place is 6.21 cm to the right of the negative charge. (a) What is the distance
between the charges? (b) Find 91/92, the ratio of the magnitudes of the charges.
V = OV
(a) Number
(b) Number
IN
+91
I
Units
Units
cm
92
V = OV

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