resultant moment and express as a Cartesian vector. 2021 Cathy Zupke M₁ X Z M3 M₂ L5 LA- y

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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**Description of the Problem:**

A pipe intersection has moments on three of its branches as depicted in the figure and parameter table. Your task is to calculate the resultant moment and express it as a Cartesian vector.

**Diagram Explanation:**

The diagram shows a 3D coordinate system with three moments, \( M_1 \), \( M_2 \), and \( M_3 \), acting along different branches of the pipe:

- \( M_1 \) acts along the negative x-direction.
- \( M_2 \) acts in a plane involving x and y axes, oriented at an angle in the positive y-direction.
- \( M_3 \) acts in the negative z-direction.

**Parameter Table:**

| Parameter | Value | Units   |
|-----------|-------|---------|
| \( L_1 \)     | 1     | ft       |
| \( L_2 \)     | 4     | ft       |
| \( L_3 \)     | 3     | ft       |
| \( L_4 \)     | 2.5   | ft       |
| \( L_5 \)     | 3     | ft       |
| \( M_1 \)     | 200   | lb·ft  |
| \( M_2 \)     | 250   | lb·ft  |
| \( M_3 \)     | 200   | lb·ft  |

**Calculation Instructions:**

To find the resultant moment as a Cartesian vector, decompose each moment vector into its i, j, and k components using the given lengths (\( L_1 \), \( L_2 \), etc.) and angles implied in the diagram.

**Note:**

Use \( i, j, k \) for the unit vectors \( \hat{i}, \hat{j}, \hat{k} \).

The resultant moment should be expressed in the following format:

\[ \text{Resultant moment} = \text{(calculated vector)} \, \text{lb·ft} \]

Fill in the box provided with the calculated resultant moment in Cartesian vector form.
Transcribed Image Text:**Description of the Problem:** A pipe intersection has moments on three of its branches as depicted in the figure and parameter table. Your task is to calculate the resultant moment and express it as a Cartesian vector. **Diagram Explanation:** The diagram shows a 3D coordinate system with three moments, \( M_1 \), \( M_2 \), and \( M_3 \), acting along different branches of the pipe: - \( M_1 \) acts along the negative x-direction. - \( M_2 \) acts in a plane involving x and y axes, oriented at an angle in the positive y-direction. - \( M_3 \) acts in the negative z-direction. **Parameter Table:** | Parameter | Value | Units | |-----------|-------|---------| | \( L_1 \) | 1 | ft | | \( L_2 \) | 4 | ft | | \( L_3 \) | 3 | ft | | \( L_4 \) | 2.5 | ft | | \( L_5 \) | 3 | ft | | \( M_1 \) | 200 | lb·ft | | \( M_2 \) | 250 | lb·ft | | \( M_3 \) | 200 | lb·ft | **Calculation Instructions:** To find the resultant moment as a Cartesian vector, decompose each moment vector into its i, j, and k components using the given lengths (\( L_1 \), \( L_2 \), etc.) and angles implied in the diagram. **Note:** Use \( i, j, k \) for the unit vectors \( \hat{i}, \hat{j}, \hat{k} \). The resultant moment should be expressed in the following format: \[ \text{Resultant moment} = \text{(calculated vector)} \, \text{lb·ft} \] Fill in the box provided with the calculated resultant moment in Cartesian vector form.
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