RESULT OF SURVEY: Based on our survey, mostly of our customers are preferable to our products which is milktea. The result is way more positive and good impact because they satisfy to buy milktea than other beverages. We have 20 respondents; products with an average rating of 5 and 2 respondents strongly disagree with an average rating of 1. Both of then have no standard deviation. 18 respondents satisfaction from the INDEPENDENT SAMPLE T-TEST 1. DEFINE THE NULL AND ALTERNATIVE
RESULT OF SURVEY: Based on our survey, mostly of our customers are preferable to our products which is milktea. The result is way more positive and good impact because they satisfy to buy milktea than other beverages. We have 20 respondents; products with an average rating of 5 and 2 respondents strongly disagree with an average rating of 1. Both of then have no standard deviation. 18 respondents satisfaction from the INDEPENDENT SAMPLE T-TEST 1. DEFINE THE NULL AND ALTERNATIVE
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
State the results for the following picture below
Transcribed Image Text:-2.101-
→2.101
If the T computed value greater than 2.101 or beyond
-2.101, the null hypothesis reject.
5. CALCULATE THE TEST STATISTICS
STRONGLY
(X²,)
STRONGLY
(X²,)
AGREE (X,)
DISAGREE (X,)
25
25
5
25
5
25
25
5
25
25
5
25
5
25
5
25
5
25
25
25
25
5
25
5
25
25
5
25
EX1= 90
1= 18
ΣΧ, 450
Σχ2
ΣΧ2
N' = 2
X? = 1
X,= 5
SOLUTION:
ss, = E x², - (E ×,)² / n,
= 450- (5)?/ 18
= 450-25 / 18
= 425
23.6
o.S
+2 -2
24.11
18
= 23.61
SS, = E x²,- (E x,)² / n,
= 2 - (1)? / 2
= 2-1 / 2
V0-7 366
=1
2
= 0.5
Transcribed Image Text:RESULT OF SURVEY:
Based on our survey, mostly of our customers are
preferable to our products which is milktea. The result is
way more positive and good impact because they satisfy
to buy milktea than other beverages. We have 20
respondents;
products with an average rating of 5 and 2 respondents
strongly disagree with an average rating of 1. Both of then
have no standard deviation.
18 respondents satisfaction from the
INDEPENDENT SAMPLE T-TEST
1.
DEFINE
THE
NULL
AND
ALTERNATIVE
HYPOTHESIS
• NULL: The customers give satisfaction rating
about the product
ALTERNATIVE:
The
customers
give
unsatisfaction rating about the product
2. STATE ALPHA
=0.05
3. CALCULATE THE DEGREES OF FREEDOM
Degrees of freedom for independent Samples T-
Test
df= (n,-1) (n,-1)
df= (18-1) (2-1) = 18
4. STATE DECISION RULE
0.05
a/20.025
-2.101+
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