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RESULT OF SURVEY: Based on our survey, mostly of our customers are preferable to our products which is milktea. The result is way more positive and good impact because they satisfy to buy milktea than other beverages. We have 20 respondents; products with an average rating of 5 and 2 respondents strongly disagree with an average rating of 1. Both of then have no standard deviation. 18 respondents satisfaction from the INDEPENDENT SAMPLE T-TEST 1. DEFINE THE NULL AND ALTERNATIVE

RESULT OF SURVEY: Based on our survey, mostly of our customers are preferable to our products which is milktea. The result is way more positive and good impact because they satisfy to buy milktea than other beverages. We have 20 respondents; products with an average rating of 5 and 2 respondents strongly disagree with an average rating of 1. Both of then have no standard deviation. 18 respondents satisfaction from the INDEPENDENT SAMPLE T-TEST 1. DEFINE THE NULL AND ALTERNATIVE

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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State the results for the following picture below
-2.101- →2.101 If the T computed value greater than 2.101 or beyond -2.101, the null hypothesis reject. 5. CALCULATE THE TEST STATISTICS STRONGLY (X²,) STRONGLY (X²,) AGREE (X,) DISAGREE (X,) 25 25 5 25 5 25 25 5 25 25 5 25 5 25 5 25 5 25 25 25 25 5 25 5 25 25 5 25 EX1= 90 1= 18 ΣΧ, 450 Σχ2 ΣΧ2 N' = 2 X? = 1 X,= 5 SOLUTION: ss, = E x², - (E ×,)² / n, = 450- (5)?/ 18 = 450-25 / 18 = 425 23.6 o.S +2 -2 24.11 18 = 23.61 SS, = E x²,- (E x,)² / n, = 2 - (1)? / 2 = 2-1 / 2 V0-7 366 =1 2 = 0.5
Transcribed Image Text:-2.101- →2.101 If the T computed value greater than 2.101 or beyond -2.101, the null hypothesis reject. 5. CALCULATE THE TEST STATISTICS STRONGLY (X²,) STRONGLY (X²,) AGREE (X,) DISAGREE (X,) 25 25 5 25 5 25 25 5 25 25 5 25 5 25 5 25 5 25 25 25 25 5 25 5 25 25 5 25 EX1= 90 1= 18 ΣΧ, 450 Σχ2 ΣΧ2 N' = 2 X? = 1 X,= 5 SOLUTION: ss, = E x², - (E ×,)² / n, = 450- (5)?/ 18 = 450-25 / 18 = 425 23.6 o.S +2 -2 24.11 18 = 23.61 SS, = E x²,- (E x,)² / n, = 2 - (1)? / 2 = 2-1 / 2 V0-7 366 =1 2 = 0.5
RESULT OF SURVEY: Based on our survey, mostly of our customers are preferable to our products which is milktea. The result is way more positive and good impact because they satisfy to buy milktea than other beverages. We have 20 respondents; products with an average rating of 5 and 2 respondents strongly disagree with an average rating of 1. Both of then have no standard deviation. 18 respondents satisfaction from the INDEPENDENT SAMPLE T-TEST 1. DEFINE THE NULL AND ALTERNATIVE HYPOTHESIS • NULL: The customers give satisfaction rating about the product ALTERNATIVE: The customers give unsatisfaction rating about the product 2. STATE ALPHA =0.05 3. CALCULATE THE DEGREES OF FREEDOM Degrees of freedom for independent Samples T- Test df= (n,-1) (n,-1) df= (18-1) (2-1) = 18 4. STATE DECISION RULE 0.05 a/20.025 -2.101+
Transcribed Image Text:RESULT OF SURVEY: Based on our survey, mostly of our customers are preferable to our products which is milktea. The result is way more positive and good impact because they satisfy to buy milktea than other beverages. We have 20 respondents; products with an average rating of 5 and 2 respondents strongly disagree with an average rating of 1. Both of then have no standard deviation. 18 respondents satisfaction from the INDEPENDENT SAMPLE T-TEST 1. DEFINE THE NULL AND ALTERNATIVE HYPOTHESIS • NULL: The customers give satisfaction rating about the product ALTERNATIVE: The customers give unsatisfaction rating about the product 2. STATE ALPHA =0.05 3. CALCULATE THE DEGREES OF FREEDOM Degrees of freedom for independent Samples T- Test df= (n,-1) (n,-1) df= (18-1) (2-1) = 18 4. STATE DECISION RULE 0.05 a/20.025 -2.101+
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