Researchers want to determine if heavier cars use more gasoline? To answer this question, a researcher randomly selected 15 cars. He collected their weight (in hundreds of pounds) and the mileage (MPG) for each car. From a scatterplot made with the data, a linear model seemed appropriate and the following output was obtained in photo below. Question: Determine the proportion of the variation in mileage is accounted for by the linear relationship with the weight of the car and also determine the estimate of the regression standard deviation.
Researchers want to determine if heavier cars use more gasoline? To answer this question, a researcher randomly selected 15 cars. He collected their weight (in hundreds of pounds) and the mileage (MPG) for each car. From a scatterplot made with the data, a linear model seemed appropriate and the following output was obtained in photo below. Question: Determine the proportion of the variation in mileage is accounted for by the linear relationship with the weight of the car and also determine the estimate of the regression standard deviation.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Researchers want to determine if heavier cars use more gasoline? To answer this question, a researcher randomly selected 15 cars. He collected their weight (in hundreds of pounds) and the mileage (MPG) for each car. From a
Question: Determine the proportion of the variation in mileage is accounted for by the linear relationship with the weight of the car and also determine the estimate of the regression standard deviation.

Transcribed Image Text:The following output was obtained from SAS:
A table displays the R-Square value and Root Mean Square Error (MSE):
- **R-Square**: 0.438
- **Root MSE**: 6.78
Another table provides the results of a regression analysis, including the parameter estimates, standard error, t-value, and p-value:
| Parameter | Estimate | Standard Error | t Value | Pr > |t| |
|-----------|----------|----------------|---------|------|
| Intercept | 40.439 | 6.275 | 6.445 | 0.0000 |
| WEIGHT | -0.521 | 0.164 | -3.182 | 0.0072 |
This output suggests that the model explains approximately 43.8% of the variance in the response variable. The intercept is 40.439, and the coefficient for the WEIGHT variable is -0.521, indicating a negative relationship. Both have statistically significant p-values.
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