Researchers conducted a study and obtained a p-value of 0.75. Based on this p-value, what conclusion should the researchers draw?Choose the correct answer below.O A. Reject the null hypothesis and accept the alternative as true.OB. Redo the study as it is not possible to get a p-value that high.OC. Reject the null hypothesis but do not accept the alternative as true.(・・・)O D. Fail to reject the null hypothesis and, therefore, accept the null hypothesis as true.O E. Fail to reject the null hypothesis but do not accept the null hypothesis as true either.

When p value is too large or greater than level of significance ɑ=0.05, then we fail to reject the…

Answered: Researchers conducted a study and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A humane society claims that less than 61% of households in a certain country own a pet. In a random sample of 700 households in that country, 399 say they own a pet. At a= 0.05, is there enough evidence to support the society's claim? Complete parts (a) through (c) below. (a) Identify the claim and state H, and Ha. Identify the claim in this scenario. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or a decimal. Do not round.) O A. The percentage households in the country' that own a pet is not %. O B. Less than % of households in the country own a pet. O C. More than % of households in the country own a pet. O D. % of hoúseholds in the country own a pet.
20. Which of the following is a null hypothesis? a. Pregnant women who drink cranberry juice will have lower urine bacterial counts than those who do not drink cranberry juice. b. The urine bacterial count of pregnant women who drink cranberry juice will be lower or equal to that of pregnant women who do not drink the juice. c. There will be a difference between ingestion of cranberry juice and among pregnant women who do and do not have high urine bacterial counts.
A publisher reports that 56 % of their readers own a particular make of car. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage. A random sample of 200 found that 47 % of the readers owned a particular make of car. State the null and alternative hypotheses. Answer 囲 Tables E Keypad Keyboard Shortcuts Ho:
60% of students entering four-year colleges receive a degree within six years. Is this percent smaller than for students who play intramural sports? 130 of the 241 students who played intramural sports received a degree within six years. What can be concluded at the level of significance of a = 0.01? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho:1?v Но: 7Select an answer v (please enter a decimal) H1:1?v|Select an answer v (Please enter a decimal) c. The test statistic ? (please show your answer to 3 decimal places.) d. The p-value (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusiion is that .. The data suggest the population proportion is not significantly smaller than 60% at a = 0.01, so there is not sufficient evidence to conclude that the population proportion of students who played intramural sports who received…
need help with B, C, D
I. M. Schurr claims that students enjoy online classes more than professors. In order to test his claim, Schurr takes a sample of 60 students and determines 80% of the students enjoy online classes. For a sample of 40 professors, Schurr finds that 55% of the professors enjoy online classes. Do the data support Schurr’s claim that students enjoy online classes more than professors? a. State the null and alternative hypothesis that would be used to test whether students enjoy online classes more than professors.b. What is the appropriate test statistic?c. Determine the critical value(s) for this test using a 1% significance level.d. Calculate the value of the test statistic.e. What is your decision and conclusion?
Answer the letter D only
Question 10: give the conclusion.
12% of all Americans suffer from sleep apnea. A researcher suspects that a different percentage of those who live in the inner city have sleep apnea. Of the 372 people from the inner city surveyed, 30 of them suffered from sleep apnea. What can be concluded at the level of significance of a = 0.10? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? v Select an answer v (please enter a decimal) H1: ? v Select an answer v (Please enter a decimal) c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? v a f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the population proportion is not significantly different from 12% at a = 0.10, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is…
13% of all Americans suffer from sleep apnea. A researcher suspects that a higher percentage of those who live in the inner city have sleep apnea. Of the 321 people from the inner city surveyed, 51 of them suffered from sleep apnea. What can be concluded at the level of significance of a = 0.01? î a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? Select an answer ↑ (please enter a decimal) H₁: ? î Select an answer (Please enter a decimal) c. The test statistic ? î = (please show your answer to 3 decimal places.) d. The p-value= = (Please show your answer to 4 decimal places.) e. The p-value is ? î a f. Based on this, we should Select an answer the null hypothesis. g. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly larger than 13% at a = 0.01, so there is not sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is larger…
Suppose that in a random selection of 100100 colored candies, 2323% of them are blue. The candy company claims that the percentage of blue candies is equal to 2727%. Use a 0.010.01 significance level to test that claim. Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. Upper H 0H0: pequals=0.270.27 Upper H 1H1: pgreater than>0.270.27 B. Upper H 0H0: pnot equals≠0.270.27 Upper H 1H1: pequals=0.270.27 C. Upper H 0H0: pequals=0.270.27 Upper H 1H1: pless than<0.270.27 D. Upper H 0H0: pequals=0.270.27 Upper H 1H1: pnot equals≠0.270.27 Your answer is correct. Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is nothing. (Round to two decimal places as needed.)

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