aces!Required information.Problem 15.001 - Wind tunnel experimentExperimental data for force (N) and velocity (m/s) from a wind tunnel experiment is mentioned in the below table.506070v, m/s 10 20 30 40F.N 25 70 380 550 610 1220 830801450Problem 15.001.b - Determine the r2 for the obtained parabolic fitDetermine the 2 for the obtained parabolic fit. (Round the final answer to five decimal palces.)The value of 2

is the velocity (m/s) and is the force (N)The following data has been…

Answered: Required information. Problem 15.001-…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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%V. 11:11 Laplace Quiz.jpg > s2+6s+8 s4+8s2+16 L-1 II
1. Find the missing legs or angles of the triangles d-? v= 52 ms 20 12 m shown. 14 m v,8 m/s d. V, 12 m's 12 m V-? [Figure 4] 2. Draw in thex-andy-velocity components for each dot along the path of the cannonball. The first one is done for you. [Figure 5]
Now measure and record the period for small angle motion with a stopwatch (there is no angle too small, so long as you can see it move). Measure the period in the following way: Move the mass away from equilibrium. Start a stopwatch and simultaneously release the mass. Stop the stopwatch after it swings 5 times back and forth. Record this value. Now acquire 5 more periods this way (each with five swings) so that you have six measures of the period of the same pendulum. Q2: What is the period of the pendulum written as mean +/- error while using a 95% confidence interval? Measurement #1: 3.17 Seconds (Period - T=0.634) Measurement #2: 2.95 Seconds (Period - T=0.590) Measurement #3: 3.25 Seconds (Period - T=0.650) Measurement #4: 3.16 Seconds (Period - T=0.632) Measurement #5: 3.17 Seconds (Period - T=0.634) Measurement #6: 3.22 Seconds (Period - T=0.644) Mean = 3.784/6=0.630 I do not understand how to produce the error +/- while using the 95% confidence interval. Could you please help…
i moodle.nct.edu.om/mod/quiz/attempt.php?attempt%3D435687&cmid=50314& Translate O YouTube Maps Google 6 l Jss lg M Gmail Courses Reports e-Services - Academic Dep CT e-Learning Portal alculus I بثقة Moving F rd / My courses / MATH1200/ Click / Self Study Activity Given a = 12 In(t) and y= 144 t then find dy out of da question d'y dz2 Given z = 13t 24 and y 169 sint Ae Ps F1 F2 F3 F4 F5 F6 F7 #3 2 4.
4). show all steps
AMATH 1B Additional Problems 1 week 2 1. The uniform slender bar has an ideal roller at its upper end A. If the coefficient of static friction at B is μ=0.50, determine the minimum angle for which equilibrium is possible. (Ans. 45°). B-0.25, 0.50 2. The automobile has a mass of 2 Mg and center of mass at G. Determine the towing force F required to move the car if the back brakes are locked, and the front wheels are free to roll. Take μ = 0.3. (Ans. 2.76 KN) 3. A stepladder consisting of two legs pinned together at C is resting on a rough floor. Will a 750 N worker be able to change the light bulb if he is re- quired to climb to a height of 1.3 m? The uniform legs AC and BC weigh 100 N and 80 N, respec- tively. The coefficient of static friction at A and B is 0.4. 1.3 m 60 60 -3.2 m 4. Determine the range of weights W for which the 100 N block is in equilibrium. All pulleys and wheels have negligible friction. P,-0.30 M-0.25 100 N 100 20°
A force of 15 Newtons stretches a spring 20 centimeters. After a 3 kilogram mass is attached to the spring, the mass is pulled down to a position √3 meters below equilibrium and released with an upward velocity of 5 meters per second. Find a. The equation of motion. b. The amplitude, period, and phase shift of the simple harmonic motion.
If a point travels on a compact disc 650 cm in 1 minute, what is the linear velocity of the point in cm per second? Use 3.14 as an approximation for and round your answer to the nearest tenth. loudy O O 39,000.0 cm per second O 6,252.5 cm per second 650 cm per second F2 10.8 cm per second 2 W F3 3 E F4 $ 4 R F5 % 5 Q Search F6 T ☆ G A 6 F7 4- Y F8 & 7 H Y + U F9 ★ * 00 8 J €1 F10 9 K a F11 0 O F12 P Prt Sc { + [ Insert 11 Del Backspace
3.1.3 Scalar Formulation Leammny val. To understand the concept of moment of a force and how to calculate it using a scalar formulation. The magnitude of the moment of a force with a magnitude F around a point O is defined as follows:Mo = Fdwhere d is the force's moment arm. The moment arm is the perpendicular distance from the axis at point O to the force's line of action. Figure Part A A stool at a restaurant is anchored to the floor. When a customer is in the process of sitting down, a horizontal force with magnitude F₁ is exerted at the top of the stool support as shown in the figure. (Figure 1) When the customer is seated, a vertical force with magnitude F2 is exerted on the stool support. If the maximum moment magnitude that the stool support can sustain about point A is M₁ = 175 lb-ft, what is the maximum height di that the stool can have if the magnitudes of the two forces are F₁ = 35.0 lb and F₂ = 135 lb ? Assume that moments acting counterclockwise about point A are positive…
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