Required informationProblem 04.057 - DEPENDENT MULTI-PART PROBLEM - ASSIGN ALL PARTSConsider the given circuit where V = 75 V.NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.VRN=IN=3 ΩwwwΩ292wwwA+6Ω Vx 0.5vxProblem 04.057.b - Norton equivalent from Thevenin with dependent source10 Q2Determine the Norton equivalent circuit at terminals a-b of the given circuit.ob

Thevenin's theorem The French engineer M.L. Thevenin discovered this theorem, which is also known as Thevenin's theorem, to convert the entire circuit into an equivalent circuit with a single voltage source and series resistance. This theorem, which may be the most popular one, can be used to estimate the voltage or current via each individual network element without having to go through the laborious process of solving a series of network equations.To find IN Load is Short Circuited By using Nodal Analysis, applying KCL at Node Vx : Vx-553+Vx6+IN-0.5Vx = 02Vx-110+Vx+6IN-3Vx = 03Vx-3Vx+6IN-110 = 06IN-110 = 06IN = 110 IN = 1106IN =18.33 A Now to Rth short circuit Voltage Source and take Test Voltage across the Load Applying KCL at node Vx : Vx3+Vx6+Vx-Vdc2 = 02Vx+Vx+3Vx-3Vdc6 = 0Vx = 3Vdc6Vx = Vdc2 Now applying KCL at Node Vdc : Vdc-Vx2-0.5Vx+Vdc10-Idc = 05Vdc-5Vx-5Vx+Vdc-10Idc = 05Vdc-10Vx+Vdc = 10Idc6Vdc-10Vdc2 = 10Idc6Vdc-5Vdc = 10Idc Vdc = 10Idc Rth = VdcIdcRth = 10IdcIdcRth = 10 Ω